Linear Inequalities

Study Action Plan (Sorted by Difficulty)
Feasible Region for Two-Variable Inequalities
Accuracy: 48%
Total Attempted27
Total Correct13
Total Incorrect14
Difficulty Level:
High
Applications of Inequalities
Accuracy: 60%
Total Attempted5
Total Correct3
Total Incorrect2
Difficulty Level:
Medium
Graphical Representation of Inequalities
Accuracy: 68%
Total Attempted31
Total Correct21
Total Incorrect10
Difficulty Level:
Medium
System of Inequalities
Accuracy: 70%
Total Attempted44
Total Correct31
Total Incorrect13
Difficulty Level:
Medium
Properties of Inequalities
Accuracy: 74%
Total Attempted38
Total Correct28
Total Incorrect10
Difficulty Level:
Medium
Linear Inequalities in Two Variables
Accuracy: 76%
Total Attempted42
Total Correct32
Total Incorrect10
Difficulty Level:
Low
Linear Inequalities in One Variable
Accuracy: 78%
Total Attempted88
Total Correct69
Total Incorrect19
Difficulty Level:
Low
Double Inequalities and Interval Solutions
Accuracy: 93%
Total Attempted43
Total Correct40
Total Incorrect3
Difficulty Level:
Low

Learning Objectives

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Learning Objectives

  • Understand and solve linear inequalities in one variable using algebraic manipulation and represent solutions graphically on a number line.
  • Graphically solve linear inequalities in two variables using half-planes, boundary lines, and test points.
  • Comprehend the properties of inequalities, including the effects of addition, subtraction, and multiplication/division by positive or negative numbers on the inequality sign.
  • Graphically represent solutions of inequalities on a number line, distinguishing between strict and slack inequalities using open and closed circles.
  • Solve systems of inequalities and represent their solutions graphically, focusing on the intersection of solution sets.
  • Apply inequalities to solve real-world problems, such as determining minimum or maximum values under given constraints.
  • Solve double inequalities and express solutions in interval notation, such as solving −8≤5x−3<7-8 \leq 5x - 3 < 7.
  • Identify the feasible region for two-variable inequalities, including boundary line inclusion/exclusion, for inequalities like ax+by≤cax + by \leq c or ax+by≥cax + by \geq c.

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Revision Notes & Summary

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Chapter Notes

Linear Inequalities in One Variable

  • Definition: An inequality involving a single variable, expressed in the form ax+b<0ax + b < 0, ax+b>0ax + b > 0, ax+b≤0ax + b \leq 0, or ax+b≥0ax + b \geq 0.
  • Example: Solve 30x<20030x < 200.
    • Solution:
      • Divide both sides by 30: x<20030x < \frac{200}{30}
      • Simplify: x<203x < \frac{20}{3}
      • If xx is a natural number, solution set: {1, 2, 3, 4, 5, 6}
      • If xx is an integer, solution set: {-3, -2, -1, 0, 1, 2, 3, 4, 5, 6}

Linear Inequalities in Two Variables

  • Definition: An inequality involving two variables, expressed in the form ax+by<cax + by < c, ax+by>cax + by > c, ax+by≤cax + by \leq c, or ax+by≥cax + by \geq c.
  • Graphical Solution:
    • Represented using half-planes and boundary lines.
    • Use test points to determine which half-plane satisfies the inequality.

Properties of Inequalities

  • Addition/Subtraction: Equal numbers can be added to or subtracted from both sides without changing the inequality.
  • Multiplication/Division:
    • By a positive number: Inequality sign remains the same.
    • By a negative number: Inequality sign is reversed.

Graphical Representation of Inequalities

  • On a Number Line:
    • Strict Inequality (<< or >>): Use open circles.
    • Slack Inequality (≤\leq or ≥\geq): Use closed circles.

System of Inequalities

  • Definition: A set of two or more inequalities with the same variables.
  • Solution: The intersection of the solution sets of the individual inequalities.
  • Graphical Representation: Use overlapping regions on a graph to find the common solution area.

Applications of Inequalities

  • Real-World Problems: Use inequalities to determine minimum or maximum values under given constraints.
  • Example: A student needs a minimum of 70 marks in the annual exam to achieve an average of at least 60 marks.

Double Inequalities and Interval Solutions

  • Example: Solve −8≤5x−3<7-8 \leq 5x - 3 < 7.
    • Solution:
      • Split into two inequalities: −8≤5x−3-8 \leq 5x - 3 and 5x−3<75x - 3 < 7.
      • Solve each separately and combine the solutions.
      • Solution set: −1≤x<2-1 \leq x < 2.

Feasible Region for Two-Variable Inequalities

  • Definition: The region that satisfies all given inequalities in a system.
  • Boundary Line Inclusion/Exclusion:
    • Solid Line: Includes the boundary (inequality with ≤\leq or ≥\geq).
    • Dashed Line: Excludes the boundary (inequality with << or >>).

Examples

  • Example 1: Solve 4x+3<6x+74x + 3 < 6x + 7.
    • Solution:
      • Rearrange: −2x<4-2x < 4
      • Divide by -2: x>−2x > -2
      • Solution set: (−2,∞)(-2, \infty)
  • Example 2: Solve 3x−2≥x+13x - 2 \geq x + 1.
    • Solution:
      • Rearrange: 2x≥32x \geq 3
      • Divide by 2: x≥32x \geq \frac{3}{2}
      • Solution set: [32,∞)[\frac{3}{2}, \infty)
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Practice Test – MCQs, True/False

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Multiple Choice Questions

A.

Multiplying both sides of an inequality by a positive number reverses the inequality sign.

B.

Adding the same number to both sides of an inequality does not affect the inequality sign.

C.

Dividing both sides of an inequality by a negative number does not affect the inequality sign.

D.

Subtracting the same number from both sides of an inequality reverses the inequality sign.
Correct Answer: B

Solution:

Adding or subtracting the same number to both sides of an inequality does not affect the inequality sign.

Chapter Concept:

Properties of Inequalities

A.

x<2x < 2

B.

x>2x > 2

C.

x≤2x \leq 2

D.

x≥2x \geq 2
Correct Answer: A

Solution:

Rearranging the inequality 5x−3<3x+15x - 3 < 3x + 1 gives 2x<42x < 4, which simplifies to x<2x < 2.

Chapter Concept:

Double Inequalities and Interval Solutions

A.

x<6x < 6

B.

x<7x < 7

C.

x<8x < 8

D.

x<9x < 9
Correct Answer: A

Solution:

Dividing both sides by 30 gives x<20030=203≈6.67x < \frac{200}{30} = \frac{20}{3} \approx 6.67. Since xx is a natural number, xx can be 1, 2, 3, 4, 5, or 6.

Chapter Concept:

Properties of Inequalities

A.

9

B.

8

C.

7

D.

6
Correct Answer: C

Solution:

Let the number of pencils be xx and the number of erasers be yy. The inequality is 5x+3y≤505x + 3y \leq 50. If y=1y = 1, then 5x+3≤50⇒5x≤47⇒x≤9.45x + 3 \leq 50 \Rightarrow 5x \leq 47 \Rightarrow x \leq 9.4. Hence, the maximum integer value of xx is 9. However, buying 9 pencils would leave no money for an eraser, so the maximum number of pencils Ravi can buy is 7, allowing for the purchase of one eraser.

Chapter Concept:

Applications of Inequalities

A.

[−1,2)[-1, 2)

B.

(−1,2](-1, 2]

C.

(−1,2)(-1, 2)

D.

[1,3)[1, 3)
Correct Answer: A

Solution:

To solve the inequality, split it into two inequalities: −8≤5x−3-8 \leq 5x - 3 and 5x−3<75x - 3 < 7. Solving the first gives x≥−1x \geq -1, and solving the second gives x<2x < 2. Thus, the solution in interval notation is $$[-1, 2)$.

Chapter Concept:

Double Inequalities and Interval Solutions

A.

86°F to 95°F

B.

80°F to 90°F

C.

84°F to 92°F

D.

88°F to 98°F
Correct Answer: A

Solution:

Using the conversion formula C=59(F−32)C = \frac{5}{9}(F - 32), substituting 30<C<3530 < C < 35 gives 86<F<9586 < F < 95. Therefore, the range in Fahrenheit is 86°F to 95°F.

Chapter Concept:

Linear Inequalities in Two Variables

A.

120 to 300 liters

B.

100 to 250 liters

C.

150 to 320 liters

D.

200 to 350 liters
Correct Answer: A

Solution:

Let xx be the liters of 30% solution added. The inequalities 30x+7200>15(x+600)30x + 7200 > 15(x + 600) and 30x+7200<18(x+600)30x + 7200 < 18(x + 600) solve to 120<x<300120 < x < 300.

Chapter Concept:

Graphical Representation of Inequalities

A.

ax+b=0ax + b = 0

B.

ax+by<cax + by < c

C.

ax2+bx+c=0ax^2 + bx + c = 0

D.

ax+b>0ax + b > 0
Correct Answer: B

Solution:

A linear inequality in two variables is represented by expressions like ax+by<cax + by < c, where aa and bb are not both zero.

Chapter Concept:

Linear Inequalities in Two Variables

A.

5

B.

10

C.

15

D.

20
Correct Answer: A

Solution:

Let xx be the score needed in the second part. Then, 70+xgeq7570 + x \\geq 75. Solving gives xgeq5x \\geq 5.

Chapter Concept:

System of Inequalities

A.

With an open circle

B.

With a closed circle

C.

With a dashed line

D.

With a solid line
Correct Answer: A

Solution:

Strict inequalities are represented with an open circle on a number line to indicate that the endpoint is not included.

Chapter Concept:

Graphical Representation of Inequalities

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True or False

Correct Answer: True

Solution:

By rearranging the terms, we get 5x−3x<1+35x - 3x < 1 + 3, which simplifies to 2x<42x < 4, hence x<2x < 2.

Chapter Concept :

Linear Inequalities in One Variable

Correct Answer: False

Solution:

When multiplying or dividing all parts of a double inequality by a negative number, the inequality signs must be reversed.

Chapter Concept :

Double Inequalities and Interval Solutions

Correct Answer: False

Solution:

The inequality 30x<20030x < 200 does not include negative integers in its solution set because xx represents the number of packets of rice, which cannot be negative.

Chapter Concept :

Applications of Inequalities

Correct Answer: True

Solution:

Dividing both sides by -5 reverses the inequality sign, resulting in x≥8x \geq 8.

Chapter Concept :

Linear Inequalities in One Variable

Correct Answer: True

Solution:

To solve the inequality −8≤5x−3<7-8 \leq 5x - 3 < 7, split it into two inequalities: −8≤5x−3-8 \leq 5x - 3 and 5x−3<75x - 3 < 7. Solving the first gives x≥−1x \geq -1 and the second gives x<2x < 2. Thus, the solution in interval notation is [−1,2)[-1, 2).

Chapter Concept :

Double Inequalities and Interval Solutions

Correct Answer: True

Solution:

The solution to a system of inequalities is the set of all points that satisfy all inequalities in the system, which is represented by the intersection of their solution sets.

Chapter Concept :

System of Inequalities

Correct Answer: False

Solution:

When both sides of an inequality are multiplied by a negative number, the inequality sign is reversed. For example, if 3>23 > 2, then multiplying both sides by −1-1 gives −3<−2-3 < -2.

Chapter Concept :

Properties of Inequalities

Correct Answer: True

Solution:

Multiplying or dividing both sides of an inequality by a negative number reverses the inequality sign. For example, if 3>23 > 2, then −3<−2-3 < -2.

Chapter Concept :

Properties of Inequalities

Correct Answer: True

Solution:

When xx is a natural number, the inequality 30x<20030x < 200 holds true for x=1,2,3,4,5,6x = 1, 2, 3, 4, 5, 6, as these values satisfy the condition 30x<20030x < 200.

Chapter Concept :

Linear Inequalities in Two Variables

Correct Answer: True

Solution:

When solving inequalities, multiplying or dividing both sides by a negative number requires reversing the inequality sign to maintain the truth of the statement.

Chapter Concept :

Linear Inequalities in One Variable

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