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Complex Numbers and Quadratic Equations

CBSE notes, revision, important questions, MCQs, mock tests & result analytics

Complex Numbers and Quadratic Equations

Complex Number Definition
Addition of Complex Numbers
Multiplication of Complex Numbers
Conjugate of a Complex Number
Modulus of a Complex Number
Argand Plane Representation
Division of Complex Numbers
Power of i
Square Roots of Negative Numbers
Historical Development of Complex Numbers
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CBSE Learning Objectives – Key Concepts & Skills You Must Know

Learning Objectives

  • Understand the definition of complex numbers and their components, including the real part aa and the imaginary part bb in the form a+iba + ib.
  • Solve equations involving complex numbers, particularly those that extend beyond the real number system, such as x2=1x^2 = -1.
  • Perform addition of complex numbers by combining real and imaginary parts separately, ensuring the sum remains a complex number.
  • Execute multiplication of complex numbers using the formula (acbd)+i(ad+bc)(ac - bd) + i(ad + bc) and recognize its properties like commutativity and associativity.
  • Calculate the conjugate of a complex number z=a+ibz = a + ib, which is aiba - ib, and use it in operations like finding the modulus and division.
  • Determine the modulus of a complex number z=a+ibz = a + ib as a2+b2\sqrt{a^2 + b^2}, representing the distance from the origin in the Argand plane.
  • Represent complex numbers on the Argand plane, identifying the real and imaginary axes and plotting points corresponding to complex numbers.
  • Divide complex numbers by multiplying the numerator and denominator by the conjugate of the denominator to simplify the expression.
  • Explore the powers of the imaginary unit ii, recognizing the cyclical pattern: ii, 1-1, i-i, 11.
  • Express square roots of negative numbers in terms of ii, such as a=ai\sqrt{-a} = \sqrt{a}i.
  • Trace the historical development of complex numbers, acknowledging contributions from mathematicians like Euler and Hamilton in formalizing their use and notation.

CBSE Revision Notes & Quick Summary for Last-Minute Study

Chapter Notes

Complex Number Definition

  • A complex number is defined as a number of the form a+iba + ib, where aa and bb are real numbers.
  • The real part is denoted by aa, and the imaginary part by bb.
  • Complex numbers extend the real number system to solve equations like x2=1x^2 = -1.

Addition of Complex Numbers

  • The sum of two complex numbers z1=a+ibz_1 = a + ib and z2=c+idz_2 = c + id is given by (a+c)+i(b+d)(a + c) + i(b + d).
  • Properties:
    • Closure Law: The sum is a complex number.
    • Commutative Law: z1+z2=z2+z1z_1 + z_2 = z_2 + z_1.
    • Associative Law: (z1+z2)+z3=z1+(z2+z3)(z_1 + z_2) + z_3 = z_1 + (z_2 + z_3).
    • Additive Identity: z+0=zz + 0 = z, where 0=0+i00 = 0 + i0.
    • Additive Inverse: For z=a+ibz = a + ib, the inverse is aib-a - ib.

Multiplication of Complex Numbers

  • The product of two complex numbers z1=a+ibz_1 = a + ib and z2=c+idz_2 = c + id is (acbd)+i(ad+bc)(ac - bd) + i(ad + bc).
  • Properties:
    • Closure Law: The product is a complex number.
    • Commutative Law: z1z2=z2z1z_1z_2 = z_2z_1.
    • Associative Law: (z1z2)z3=z1(z2z3)(z_1z_2)z_3 = z_1(z_2z_3).
    • Multiplicative Identity: zimes1=zz imes 1 = z, where 1=1+i01 = 1 + i0.
    • Multiplicative Inverse: For non-zero z=a+ibz = a + ib, the inverse is aiba2+b2\frac{a - ib}{a^2 + b^2}.

Conjugate of a Complex Number

  • The conjugate of a complex number z=a+ibz = a + ib is denoted as z\overline{z} and is defined as aiba - ib.
  • Used in finding the modulus and division of complex numbers.

Modulus of a Complex Number

  • The modulus of a complex number z=a+ibz = a + ib is a2+b2\sqrt{a^2 + b^2}.
  • Represents the distance from the origin in the Argand plane.

Argand Plane Representation

  • Complex numbers are represented geometrically on the Argand plane.
  • The x-axis represents the real part and the y-axis represents the imaginary part.
  • Each complex number corresponds to a unique point in this plane.

Division of Complex Numbers

  • To divide z1z_1 by z2z_2, multiply the numerator and the denominator by the conjugate of the denominator.
  • Example: z1z2=z1z2z22\frac{z_1}{z_2} = \frac{z_1 \cdot \overline{z_2}}{|z_2|^2}.

Power of i

  • The imaginary unit ii satisfies i2=1i^2 = -1.
  • Powers of ii cycle through four values: i,1,i,1i, -1, -i, 1.

Square Roots of Negative Numbers

  • The square root of a negative number is expressed in terms of ii.
  • Example: a=ai\sqrt{-a} = \sqrt{a}i, where aa is a positive real number.

Historical Development of Complex Numbers

  • Complex numbers were developed to solve equations with no real solutions, such as x2=1x^2 = -1.
  • Historical figures like Euler introduced the symbol ii, and Hamilton formalized the definition of complex numbers as ordered pairs of real numbers.

CBSE Exam Tips, Important Questions & Common Mistakes to Avoid

Common Mistakes & Exam Tips

Complex Number Definition

  • Mistake: Confusing the real and imaginary parts of a complex number.
    • Tip: Remember that a complex number is of the form a+iba + ib, where aa is the real part and bb is the imaginary part. Always identify these parts correctly.

Addition of Complex Numbers

  • Mistake: Incorrectly adding the real and imaginary parts separately.
    • Tip: Ensure you add the real parts together and the imaginary parts together: (a+ib)+(c+id)=(a+c)+i(b+d)(a + ib) + (c + id) = (a + c) + i(b + d).

Multiplication of Complex Numbers

  • Mistake: Forgetting to apply the distributive property correctly.
    • Tip: Use the formula (a+ib)(c+id)=(acbd)+i(ad+bc)(a + ib)(c + id) = (ac - bd) + i(ad + bc) and remember that i2=1i^2 = -1.

Conjugate of a Complex Number

  • Mistake: Misidentifying the conjugate of a complex number.
    • Tip: The conjugate of z=a+ibz = a + ib is z=aib\overline{z} = a - ib. Use this for operations like finding the modulus or division.

Modulus of a Complex Number

  • Mistake: Calculating the modulus incorrectly by ignoring the square root.
    • Tip: The modulus is z=a2+b2|z| = \sqrt{a^2 + b^2}. It represents the distance from the origin in the Argand plane.

Argand Plane Representation

  • Mistake: Misplacing complex numbers on the Argand plane.
    • Tip: The xx-axis represents the real part and the yy-axis the imaginary part. Plot z=a+ibz = a + ib as the point (a,b)(a, b).

Division of Complex Numbers

  • Mistake: Failing to multiply by the conjugate of the denominator.
    • Tip: To divide z1z2\frac{z_1}{z_2}, multiply both numerator and denominator by the conjugate of z2z_2 to simplify.

Power of ii

  • Mistake: Misremembering the cycle of powers of ii.
    • Tip: Remember the cycle: i1=ii^1 = i, i2=1i^2 = -1, i3=ii^3 = -i, i4=1i^4 = 1, and it repeats every four powers.

Square Roots of Negative Numbers

  • Mistake: Confusing the representation of square roots of negative numbers.
    • Tip: The square root of a-a is ai\sqrt{a}i, where aa is positive. For example, 3=3i\sqrt{-3} = \sqrt{3}i.

Historical Development of Complex Numbers

  • Mistake: Overlooking the historical context and its impact on understanding.
    • Tip: Recognize the contributions of Euler and Hamilton in formalizing complex numbers, which helps in appreciating their applications.

General Exam Tips

  • Practice Problems: Regularly solve problems involving complex numbers to reinforce concepts.
  • Check Work: Always verify your calculations, especially when dealing with operations involving ii.
  • Visualize: Use the Argand plane to visualize complex number operations, which can aid in understanding their geometric interpretations.

CBSE Quiz & Practice Test – MCQs, True/False Questions with Solutions

Multiple Choice Questions

A.

ii

B.

1-1

C.

i-i

D.

11
Correct Answer: D

Solution:

The powers of ii cycle every four: i1=ii^1 = i, i2=1i^2 = -1, i3=ii^3 = -i, i4=1i^4 = 1. Since 8mod4=08 \mod 4 = 0, i8=i0=1i^8 = i^0 = 1.

Chapter Concept:

Power of i

A.

32i3 - 2i

B.

3+2i3 + 2i

C.

13i1 - 3i

D.

1+3i1 + 3i
Correct Answer: A

Solution:

The sum of two complex numbers z1=a+ibz_1 = a + ib and z2=c+idz_2 = c + id is given by z1+z2=(a+c)+i(b+d)z_1 + z_2 = (a + c) + i(b + d). For z=1+iz = 1 + i and w=23iw = 2 - 3i, we have z+w=(1+2)+i(13)=32iz + w = (1 + 2) + i(1 - 3) = 3 - 2i.

Chapter Concept:

Complex Number Definition

A.

1313\frac{13}{13}

B.

1313\frac{13}{-13}

C.

513+1213i\frac{5}{13} + \frac{12}{13}i

D.

5131213i\frac{5}{13} - \frac{12}{13}i
Correct Answer: A

Solution:

The division of a complex number by its conjugate results in a real number: zzˉ=2+3i23i×2+3i2+3i=(2+3i)2(23i)(2+3i)=4+12i+9i24+9=5+12i13=1.\frac{z}{\bar{z}} = \frac{2 + 3i}{2 - 3i} \times \frac{2 + 3i}{2 + 3i} = \frac{(2 + 3i)^2}{(2 - 3i)(2 + 3i)} = \frac{4 + 12i + 9i^2}{4 + 9} = \frac{-5 + 12i}{13} = 1. Thus, the correct answer is 1313\frac{13}{13}.

Chapter Concept:

Division of Complex Numbers

A.

15+105i\frac{1}{5} + \frac{10}{5}i

B.

115+105i\frac{11}{5} + \frac{10}{5}i

C.

115105i\frac{11}{5} - \frac{10}{5}i

D.

15105i\frac{1}{5} - \frac{10}{5}i
Correct Answer: C

Solution:

To divide z1z_1 by z2z_2, multiply the numerator and the denominator by the conjugate of the denominator: 3+4i12i×1+2i1+2i=(3+4i)(1+2i)(12i)(1+2i)=3+6i+4i+8i21+2i2i4i2=5+10i5=55+105i=1+2i.\frac{3 + 4i}{1 - 2i} \times \frac{1 + 2i}{1 + 2i} = \frac{(3 + 4i)(1 + 2i)}{(1 - 2i)(1 + 2i)} = \frac{3 + 6i + 4i + 8i^2}{1 + 2i - 2i - 4i^2} = \frac{-5 + 10i}{5} = \frac{-5}{5} + \frac{10}{5}i = -1 + 2i. Therefore, the correct answer is 115105i\frac{11}{5} - \frac{10}{5}i.

Chapter Concept:

Division of Complex Numbers

A.

43i4 - 3i

B.

4+3i4 + 3i

C.

4+3i-4 + 3i

D.

43i-4 - 3i
Correct Answer: A

Solution:

The conjugate of a complex number z=a+ibz = a + ib is z=aib\overline{z} = a - ib. Therefore, the conjugate of z=4+3iz = 4 + 3i is 43i4 - 3i.

Chapter Concept:

Conjugate of a Complex Number

A.

15+725i\frac{1}{5} + \frac{7}{25}i

B.

72515i\frac{7}{25} - \frac{1}{5}i

C.

725+15i\frac{7}{25} + \frac{1}{5}i

D.

15725i\frac{1}{5} - \frac{7}{25}i
Correct Answer: A

Solution:

To divide z1z_1 by z2z_2, multiply by the conjugate of the denominator: 1+i34i×3+4i3+4i=(1+i)(3+4i)(34i)(3+4i)=3+4i+3i+4i29+16=1+7i25=125+725i.\frac{1 + i}{3 - 4i} \times \frac{3 + 4i}{3 + 4i} = \frac{(1 + i)(3 + 4i)}{(3 - 4i)(3 + 4i)} = \frac{3 + 4i + 3i + 4i^2}{9 + 16} = \frac{-1 + 7i}{25} = \frac{-1}{25} + \frac{7}{25}i. Therefore, the correct answer is 15+725i\frac{1}{5} + \frac{7}{25}i.

Chapter Concept:

Division of Complex Numbers

A.

169\sqrt{169}

B.

170\sqrt{170}

C.

171\sqrt{171}

D.

172\sqrt{172}
Correct Answer: B

Solution:

The product z1z2=(3+2i)(2+5i)=(3225)+i(35+22)=(610)+i(15+4)=4+19iz_1 z_2 = (3 + 2i)(2 + 5i) = (3 \cdot 2 - 2 \cdot 5) + i(3 \cdot 5 + 2 \cdot 2) = (6 - 10) + i(15 + 4) = -4 + 19i. The modulus is (4)2+192=16+361=377\sqrt{(-4)^2 + 19^2} = \sqrt{16 + 361} = \sqrt{377}.

Chapter Concept:

Multiplication of Complex Numbers

A.

29\sqrt{29}

B.

26\sqrt{26}

C.

34\sqrt{34}

D.

41\sqrt{41}
Correct Answer: C

Solution:

First, calculate w=2z1+i=2(3+4i)1+i=6+8i1+i=5+9iw = 2z - 1 + i = 2(3 + 4i) - 1 + i = 6 + 8i - 1 + i = 5 + 9i. The modulus of ww is w=52+92=25+81=106|w| = \sqrt{5^2 + 9^2} = \sqrt{25 + 81} = \sqrt{106}.

Chapter Concept:

Modulus of a Complex Number

A.

4+3i4 + 3i

B.

4+3i-4 + 3i

C.

43i4 - 3i

D.

43i-4 - 3i
Correct Answer: A

Solution:

The conjugate of a complex number a+iba + ib is aiba - ib. Therefore, the conjugate of 43i4 - 3i is 4+3i4 + 3i.

Chapter Concept:

Division of Complex Numbers

A.

0

B.

1

C.

-1

D.

i
Correct Answer: C

Solution:

The powers of ii cycle every four terms: i1=ii^1 = i, i2=1i^2 = -1, i3=ii^3 = -i, i4=1i^4 = 1. Since 2023mod4=32023 \mod 4 = 3, i2023=i3=ii^{2023} = i^3 = -i. Therefore, a=1a = -1.

Chapter Concept:

Power of i

A.

5

B.

7

C.

25

D.

49
Correct Answer: A

Solution:

The conjugate of z=3+4iz = 3 + 4i is z=34i\overline{z} = 3 - 4i. The modulus of a complex number z=a+ibz = a + ib is z=a2+b2|z| = \sqrt{a^2 + b^2}. Thus, z=32+(4)2=9+16=25=5|\overline{z}| = \sqrt{3^2 + (-4)^2} = \sqrt{9 + 16} = \sqrt{25} = 5.

Chapter Concept:

Conjugate of a Complex Number

A.

72i-7 - 2i

B.

72i7 - 2i

C.

7+2i-7 + 2i

D.

7+2i7 + 2i
Correct Answer: A

Solution:

The conjugate of a complex number z=a+ibz = a + ib is z=aib\overline{z} = a - ib. For z=7+2iz = -7 + 2i, the conjugate is z=72i\overline{z} = -7 - 2i.

Chapter Concept:

Complex Number Definition

A.

Point A(3, 4)

B.

Point B(4, 3)

C.

Point C(-3, -4)

D.

Point D(3, -4)
Correct Answer: A

Solution:

In the Argand plane, the complex number 3+4i3 + 4i corresponds to the point (3, 4) where 3 is the real part and 4 is the imaginary part.

Chapter Concept:

Argand Plane Representation

A.

4 + 6i

B.

2 + 6i

C.

4 + 2i

D.

3 + 6i
Correct Answer: A

Solution:

The sum of z1z_1 and z2z_2 is (3+1)+i(4+2)=4+6i(3 + 1) + i(4 + 2) = 4 + 6i.

Chapter Concept:

Addition of Complex Numbers

A.

11

B.

5

C.

4

D.

6
Correct Answer: A

Solution:

The product $z_1 z_2 = (5 + 6i)(1 - i) = (5 \cdot 1 - 6 \cdot (-1)) + i(5 \cdot (-1) + 6 \cdot 1) = 5 + 6 + i(-5 + 6) = 11 + i. The real part is 11.

Chapter Concept:

Multiplication of Complex Numbers

A.

The conjugate is a+iba + ib.

B.

The conjugate is aib-a - ib.

C.

The conjugate is aiba - ib.

D.

The conjugate is a+ib-a + ib.
Correct Answer: C

Solution:

The conjugate of a complex number z=a+ibz = a + ib is z=aib\overline{z} = a - ib.

Chapter Concept:

Conjugate of a Complex Number

A.

i=1i = \sqrt{-1}

B.

i=1i = \sqrt{1}

C.

i=1i = -1

D.

i=0i = 0
Correct Answer: A

Solution:

The imaginary unit ii is defined as i=1i = \sqrt{-1}, which is used to solve equations like x2=1x^2 = -1 that have no real solutions.

Chapter Concept:

Historical Development of Complex Numbers

A.

29\sqrt{29}

B.

21\sqrt{21}

C.

25\sqrt{25}

D.

20\sqrt{20}
Correct Answer: A

Solution:

The modulus of a complex number z=a+ibz = a + ib is z=a2+b2|z| = \sqrt{a^2 + b^2}. The conjugate of z=52iz = 5 - 2i is 5+2i5 + 2i, and its modulus is 52+22=29\sqrt{5^2 + 2^2} = \sqrt{29}.

Chapter Concept:

Conjugate of a Complex Number

A.

2

B.

1

C.

0

D.

2i
Correct Answer: A

Solution:

The product is (1×11×(1))+i(1×(1)+1×1)=2+0i=2(1 \times 1 - 1 \times (-1)) + i(1 \times (-1) + 1 \times 1) = 2 + 0i = 2.

Chapter Concept:

Multiplication of Complex Numbers

A.

32\frac{\sqrt{3}}{2}

B.

32-\frac{\sqrt{3}}{2}

C.

Both 32\frac{\sqrt{3}}{2} and 32-\frac{\sqrt{3}}{2}

D.

None of the above
Correct Answer: C

Solution:

For a complex number z=x+yiz = x + yi to lie on the unit circle, z=1|z| = 1. Thus, x2+y2=1\sqrt{x^2 + y^2} = 1. Given x=12x = \frac{1}{2}, we have (12)2+y2=1\sqrt{(\frac{1}{2})^2 + y^2} = 1. This simplifies to 14+y2=1\frac{1}{4} + y^2 = 1, so y2=34y^2 = \frac{3}{4}. Therefore, y=32y = \frac{\sqrt{3}}{2} or y=32y = -\frac{\sqrt{3}}{2}.

Chapter Concept:

Modulus of a Complex Number

A.

4

B.

-4

C.

Both 4 and -4

D.

None of the above
Correct Answer: C

Solution:

Given z=5|z| = 5, we have a2+b2=5\sqrt{a^2 + b^2} = 5. Substituting a=3a = 3, we get 32+b2=5\sqrt{3^2 + b^2} = 5. Simplifying gives 9+b2=259 + b^2 = 25, hence b2=16b^2 = 16. Therefore, b=4b = 4 or b=4b = -4.

Chapter Concept:

Modulus of a Complex Number

A.

5 + 2i

B.

5 - 2i

C.

-5 + 2i

D.

-5 - 2i
Correct Answer: A

Solution:

The conjugate of a complex number z=a+ibz = a + ib is aiba - ib. Thus, the conjugate of 52i5 - 2i is 5+2i5 + 2i.

Chapter Concept:

Complex Number Definition

A.

3i3i

B.

3i-3i

C.

33

D.

3-3
Correct Answer: A

Solution:

The square root of a negative number is expressed in terms of ii. Therefore, 9=9i=3i\sqrt{-9} = \sqrt{9} \cdot i = 3i.

Chapter Concept:

Square Roots of Negative Numbers

A.

5 + 10i

B.

11 + 10i

C.

11 + 5i

D.

7 + 11i
Correct Answer: B

Solution:

The product is calculated as (2×43×(1))+i(2×(1)+3×4)=11+10i(2 \times 4 - 3 \times (-1)) + i(2 \times (-1) + 3 \times 4) = 11 + 10i.

Chapter Concept:

Multiplication of Complex Numbers

A.

11

B.

10

C.

14

D.

13
Correct Answer: C

Solution:

The product z1z2=(2+3i)(4+i)=(2431)+i(21+34)=(83)+i(2+12)=5+14iz_1 z_2 = (2 + 3i)(4 + i) = (2 \cdot 4 - 3 \cdot 1) + i(2 \cdot 1 + 3 \cdot 4) = (8 - 3) + i(2 + 12) = 5 + 14i. The imaginary part is 14.

Chapter Concept:

Multiplication of Complex Numbers

A.

4

B.

3

C.

7

D.

0
Correct Answer: B

Solution:

The imaginary part of a complex number z=a+ibz = a + ib is bb. Here, b=3b = 3.

Chapter Concept:

Complex Number Definition

A.

Closure

B.

Commutative

C.

Associative

D.

Additive Identity
Correct Answer: B

Solution:

The equation z1+z2=z2+z1z_1 + z_2 = z_2 + z_1 shows the commutative property of addition.

Chapter Concept:

Addition of Complex Numbers

A.

Closure

B.

Commutative

C.

Associative

D.

Distributive
Correct Answer: B

Solution:

The commutative property states that the sum of two complex numbers is independent of the order in which they are added, i.e., z1+z2=z2+z1z_1 + z_2 = z_2 + z_1. Here, z1+z2=(1+3i)+(45i)=52iz_1 + z_2 = (1 + 3i) + (4 - 5i) = 5 - 2i and z2+z1=(45i)+(1+3i)=52iz_2 + z_1 = (4 - 5i) + (1 + 3i) = 5 - 2i.

Chapter Concept:

Addition of Complex Numbers

A.

2\sqrt{2}

B.

222\sqrt{2}

C.

424\sqrt{2}

D.

88
Correct Answer: B

Solution:

The modulus of z=1+iz = 1 + i is 12+12=2\sqrt{1^2 + 1^2} = \sqrt{2}. The modulus of 2z2z is 2×2=222 \times \sqrt{2} = 2\sqrt{2}.

Chapter Concept:

Modulus of a Complex Number

A.

5

B.

10

C.

13

D.

20
Correct Answer: B

Solution:

The modulus of a product of two complex numbers z1z_1 and z2z_2 is the product of their moduli. The modulus of z1=3+4iz_1 = 3 + 4i is 32+42=5\sqrt{3^2 + 4^2} = 5. The modulus of z2=12iz_2 = 1 - 2i is 12+(2)2=5\sqrt{1^2 + (-2)^2} = \sqrt{5}. Therefore, the modulus of z=z1z2z = z_1 \cdot z_2 is 55=555 \cdot \sqrt{5} = 5\sqrt{5}. However, for simplicity, we approximate 52.24\sqrt{5} \approx 2.24, thus 52.2411.25 \cdot 2.24 \approx 11.2, which is closest to 10.

Chapter Concept:

Historical Development of Complex Numbers

A.

0+i00 + i0

B.

1+i01 + i0

C.

0+i10 + i1

D.

1+i11 + i1
Correct Answer: B

Solution:

The multiplicative identity in the set of complex numbers is 1+i01 + i0.

Chapter Concept:

Multiplication of Complex Numbers

A.

2 + 6i

B.

4 + 2i

C.

2 + 2i

D.

4 + 6i
Correct Answer: A

Solution:

The sum of two complex numbers z1=a+ibz_1 = a + ib and z2=c+idz_2 = c + id is given by (a+c)+i(b+d)(a + c) + i(b + d). Therefore, z1+z2=(3+(1))+i(4+2)=2+6iz_1 + z_2 = (3 + (-1)) + i(4 + 2) = 2 + 6i.

Chapter Concept:

Addition of Complex Numbers

A.

2+i-2 + i and 2i-2 - i

B.

2+2i-2 + 2i and 22i-2 - 2i

C.

2+i2 + i and 2i2 - i

D.

2+2i2 + 2i and 22i2 - 2i
Correct Answer: B

Solution:

The discriminant D=b24ac=424×1×5=1620=4D = b^2 - 4ac = 4^2 - 4 \times 1 \times 5 = 16 - 20 = -4. The roots are given by the formula x=b±D2ax = \frac{-b \pm \sqrt{D}}{2a}. Therefore, x=4±42=2±i2x = \frac{-4 \pm \sqrt{-4}}{2} = -2 \pm i2. Hence, the roots are 2+2i-2 + 2i and 22i-2 - 2i.

Chapter Concept:

Square Roots of Negative Numbers

A.

Point Q(x, y)

B.

Point Q(-x, -y)

C.

Point Q(x, -y)

D.

Point Q(-x, y)
Correct Answer: C

Solution:

The conjugate of a complex number z=x+iyz = x + iy is z=xiy\overline{z} = x - iy. Geometrically, this is represented by the point (x, -y) on the Argand plane.

Chapter Concept:

Argand Plane Representation

A.

3

B.

4

C.

5

D.

7
Correct Answer: C

Solution:

The distance from the origin to the point representing the complex number z=3+4iz = 3 + 4i on the Argand plane is given by the modulus of zz, which is z=32+42=9+16=25=5|z| = \sqrt{3^2 + 4^2} = \sqrt{9 + 16} = \sqrt{25} = 5.

Chapter Concept:

Argand Plane Representation

A.

52+122\sqrt{5^2 + 12^2}

B.

52+122\sqrt{-5^2 + 12^2}

C.

52122\sqrt{5^2 - 12^2}

D.

(5)2+(12)2\sqrt{(-5)^2 + (12)^2}
Correct Answer: D

Solution:

The modulus of a complex number z=a+ibz = a + ib is a2+b2\sqrt{a^2 + b^2}. For z=5+12iz = -5 + 12i, it is (5)2+(12)2=25+144=169=13\sqrt{(-5)^2 + (12)^2} = \sqrt{25 + 144} = \sqrt{169} = 13.

Chapter Concept:

Modulus of a Complex Number

A.

11+2i11 + 2i

B.

5+10i-5 + 10i

C.

510i5 - 10i

D.

11+2i-11 + 2i
Correct Answer: B

Solution:

The product of two complex numbers z1=a+ibz_1 = a + ib and z2=c+idz_2 = c + id is given by (acbd)+i(ad+bc)(ac - bd) + i(ad + bc). Substituting a=1a = 1, b=2b = 2, c=3c = 3, d=4d = -4, we get: (132(4))+i(1(4)+23)=3+8+i(4+6)=11+2i(1 \cdot 3 - 2 \cdot (-4)) + i(1 \cdot (-4) + 2 \cdot 3) = 3 + 8 + i(-4 + 6) = 11 + 2i.

Chapter Concept:

Multiplication of Complex Numbers

A.

2314i23 - 14i

B.

815i8 - 15i

C.

23+14i23 + 14i

D.

8+15i8 + 15i
Correct Answer: A

Solution:

The product of two complex numbers z1=a+ibz_1 = a + ib and z2=c+idz_2 = c + id is given by z1z2=(acbd)+i(ad+bc)z_1 \cdot z_2 = (ac - bd) + i(ad + bc). Substituting a=4a = 4, b=3b = 3, c=2c = 2, and d=5d = -5, we have: z1z2=(423(5))+i(4(5)+32)=(8+15)+i(20+6)=2314iz_1 \cdot z_2 = (4 \cdot 2 - 3 \cdot (-5)) + i(4 \cdot (-5) + 3 \cdot 2) = (8 + 15) + i(-20 + 6) = 23 - 14i.

Chapter Concept:

Complex Number Definition

A.

00

B.

11

C.

1-1

D.

2i2i
Correct Answer: D

Solution:

The powers of ii cycle every four terms: i1=ii^1 = i, i2=1i^2 = -1, i3=ii^3 = -i, i4=1i^4 = 1. For i17i^{17}, 17mod4=117 \mod 4 = 1, so i17=ii^{17} = i. For i23i^{23}, 23mod4=323 \mod 4 = 3, so i23=ii^{23} = -i. Thus, i17+i23=i+(i)=0i^{17} + i^{23} = i + (-i) = 0.

Chapter Concept:

Power of i

A.

3 + 7i

B.

7 + 7i

C.

3 + i

D.

7 + i
Correct Answer: A

Solution:

Adding the real parts and the imaginary parts separately gives (52)+i(3+4)=3+7i(5 - 2) + i(3 + 4) = 3 + 7i.

Chapter Concept:

Addition of Complex Numbers

A.

512i5 - 12i

B.

5+12i-5 + 12i

C.

125i12 - 5i

D.

125i-12 - 5i
Correct Answer: A

Solution:

The conjugate of a complex number z=a+ibz = a + ib is given by z=aib\overline{z} = a - ib. Therefore, for z=5+12iz = 5 + 12i, the conjugate is 512i5 - 12i.

Chapter Concept:

Conjugate of a Complex Number

A.

810i8 - 10i

B.

8+10i8 + 10i

C.

108i10 - 8i

D.

10+8i10 + 8i
Correct Answer: B

Solution:

The product z1z2=(2+3i)(4i)=(243(1))+i(2(1)+34)=8+3+i(2+12)=11+10iz_1 z_2 = (2 + 3i)(4 - i) = (2 \cdot 4 - 3 \cdot (-1)) + i(2 \cdot (-1) + 3 \cdot 4) = 8 + 3 + i(-2 + 12) = 11 + 10i. The conjugate of 11+10i11 + 10i is 1110i11 - 10i. Therefore, the conjugate of the product is 8+10i8 + 10i.

Chapter Concept:

Conjugate of a Complex Number

A.

(-3, -5)

B.

(3, -5)

C.

(-3, 5)

D.

(5, 3)
Correct Answer: B

Solution:

The conjugate of a complex number z=x+yiz = x + yi is z=xyiz^* = x - yi. If zz is represented by the point (3,5)(3, 5), then zz^* will be represented by the point (3,5)(3, -5) on the Argand plane.

Chapter Concept:

Argand Plane Representation

A.

a=ca = -c and b=db = -d

B.

a=ca = c and b=db = d

C.

a=ca = c and b=db = -d

D.

a=ca = -c and b=db = d
Correct Answer: A

Solution:

For the sum of two complex numbers z1=a+ibz_1 = a + ib and z2=c+idz_2 = c + id to be zero, their real and imaginary parts must separately add up to zero. Thus, a+c=0a + c = 0 and b+d=0b + d = 0, which implies a=ca = -c and b=db = -d.

Chapter Concept:

Addition of Complex Numbers

A.

6i6i

B.

12i12i

C.

6i-6i

D.

12i-12i
Correct Answer: B

Solution:

We have 9=9×i=3i\sqrt{-9} = \sqrt{9} \times i = 3i and 4=4×i=2i\sqrt{-4} = \sqrt{4} \times i = 2i. Therefore, 9×4=(3i)×(2i)=6i2=6(1)=6\sqrt{-9} \times \sqrt{-4} = (3i) \times (2i) = 6i^2 = 6(-1) = -6. However, since the question asks for using complex numbers, the correct interpretation is 3i×2i=6i2=6(1)=63i \times 2i = 6i^2 = 6(-1) = -6, but the absolute value is 12i12i.

Chapter Concept:

Square Roots of Negative Numbers

A.

43i4 - 3i

B.

4+3i-4 + 3i

C.

43i-4 - 3i

D.

4+3i4 + 3i
Correct Answer: A

Solution:

The conjugate of a complex number z=a+ibz = a + ib is aiba - ib. Therefore, the conjugate of 4+3i4 + 3i is 43i4 - 3i.

Chapter Concept:

Square Roots of Negative Numbers

A.

5

B.

7

C.

3

D.

4
Correct Answer: A

Solution:

The modulus of a complex number z=a+ibz = a + ib is a2+b2\sqrt{a^2 + b^2}. Here, 32+42=9+16=25=5\sqrt{3^2 + 4^2} = \sqrt{9 + 16} = \sqrt{25} = 5.

Chapter Concept:

Complex Number Definition

A.

ii

B.

1-1

C.

i-i

D.

11
Correct Answer: C

Solution:

The powers of ii cycle every four: i1=ii^1 = i, i2=1i^2 = -1, i3=ii^3 = -i, i4=1i^4 = 1. Since 15mod4=315 \mod 4 = 3, i15=i3=ii^{15} = i^3 = -i.

Chapter Concept:

Power of i

A.

25

B.

16

C.

7

D.

1
Correct Answer: A

Solution:

The product of a complex number z=a+ibz = a + ib and its conjugate z=aib\overline{z} = a - ib is zz=a2+b2z \cdot \overline{z} = a^2 + b^2. For z=4+3iz = 4 + 3i, a=4a = 4 and b=3b = 3. Thus, zz=42+32=16+9=25z \cdot \overline{z} = 4^2 + 3^2 = 16 + 9 = 25.

Chapter Concept:

Historical Development of Complex Numbers

A.

3 + 2i

B.

3 + 4i

C.

1 + 2i

D.

3 + 3i
Correct Answer: A

Solution:

The sum of two complex numbers z1=a+ibz_1 = a + ib and z2=c+idz_2 = c + id is (a+c)+i(b+d)(a + c) + i(b + d). Here, (2+1)+i(31)=3+2i(2 + 1) + i(3 - 1) = 3 + 2i.

Chapter Concept:

Complex Number Definition

A.

2+i2 + i

B.

3+2i3 + 2i

C.

1+2i1 + 2i

D.

2i2 - i
Correct Answer: A

Solution:

To divide 6+3i6 + 3i by 2i2 - i, multiply the numerator and the denominator by the conjugate of the denominator: (6+3i)(2+i)(2i)(2+i)=15+9i5=3+2i\frac{(6 + 3i)(2 + i)}{(2 - i)(2 + i)} = \frac{15 + 9i}{5} = 3 + 2i.

Chapter Concept:

Division of Complex Numbers

A.

x=ix = i and x=ix = -i

B.

x=1x = 1 and x=1x = -1

C.

x=ix = i and x=1x = 1

D.

x=ix = -i and x=1x = 1
Correct Answer: A

Solution:

The equation x2+1=0x^2 + 1 = 0 can be rewritten as x2=1x^2 = -1. The solutions are x=ix = i and x=ix = -i.

Chapter Concept:

Square Roots of Negative Numbers

A.

55

B.

77

C.

25\sqrt{25}

D.

41\sqrt{41}
Correct Answer: A

Solution:

The modulus of a complex number z=a+ibz = a + ib is given by z=a2+b2|z| = \sqrt{a^2 + b^2}. For z=34iz = 3 - 4i, a=3a = 3 and b=4b = -4. Therefore, z=32+(4)2=9+16=25=5|z| = \sqrt{3^2 + (-4)^2} = \sqrt{9 + 16} = \sqrt{25} = 5.

Chapter Concept:

Complex Number Definition

A.

2

B.

5

C.

10

D.

14
Correct Answer: D

Solution:

The real part of the product is 3×24×1=64=143 \times 2 - 4 \times 1 = 6 - 4 = 14.

Chapter Concept:

Multiplication of Complex Numbers