Binomial Theorem

Study Action Plan (Sorted by Difficulty)
General Term and Middle Term
Accuracy: 40%
Total Attempted10
Total Correct4
Total Incorrect6
Difficulty Level:
High
Binomial Identities and Divisibility Applications
Accuracy: 44%
Total Attempted9
Total Correct4
Total Incorrect5
Difficulty Level:
High
Binomial Coefficients
Accuracy: 50%
Total Attempted14
Total Correct7
Total Incorrect7
Difficulty Level:
Medium
Proof by Mathematical Induction for Binomial Theorem
Accuracy: 50%
Total Attempted8
Total Correct4
Total Incorrect4
Difficulty Level:
Medium
Pascal's Triangle
Accuracy: 58%
Total Attempted19
Total Correct11
Total Incorrect8
Difficulty Level:
Medium
Binomial Theorem for Positive Integral Indices
Accuracy: 58%
Total Attempted12
Total Correct7
Total Incorrect5
Difficulty Level:
Medium
Numerical Evaluation Using Binomial Theorem
Accuracy: 84%
Total Attempted19
Total Correct16
Total Incorrect3
Difficulty Level:
Low
Special Cases of Binomial Expansion
Accuracy: 100%
Total Attempted5
Total Correct5
Total Incorrect0
Difficulty Level:
Low

Learning Objectives

Top

Learning Objectives

  • Understand the Binomial Theorem for Positive Integral Indices and its application in expanding expressions of the form (a+b)n(a + b)^n.
  • Analyze the structure and use of Pascal's Triangle to determine binomial coefficients for expansions.
  • Prove the binomial theorem using Mathematical Induction, establishing the base case and proving the inductive step.
  • Calculate Binomial Coefficients using combinations and apply them in expansions.
  • Explore Special Cases of Binomial Expansion, such as (x−y)n(x - y)^n, and apply simplifications for specific values of aa and bb.
  • Determine the General Term and Middle Term in binomial expansions, using the formula Tr+1=(nr)an−rbrT_{r+1} = \binom{n}{r} a^{n-r} b^r.
  • Perform Numerical Evaluation Using Binomial Theorem for expressions like (98)5(98)^5 and (101)4(101)^4.
  • Prove Binomial Identities and Divisibility Applications, such as showing that 6n−5n6^n - 5n leaves a remainder of 1 when divided by 25.

Practice, Analyze & Improve

Dont just read—test your knowledge! Unlock the Student Workspace to take chapter tests and get instant performance insights.

Deep Analytics

Peer Comparison

Track Progress

Claim Free Account100% Free • No credit card required

Revision Notes & Summary

Top

Chapter Notes

Binomial Theorem for Positive Integral Indices

  • Definition: The binomial theorem provides a formula for expanding expressions of the form (a+b)n(a + b)^n, where nn is a positive integer.
  • Expansion: (a+b)n=∑k=0n(nk)an−kbk(a + b)^n = \sum_{k=0}^{n} \binom{n}{k} a^{n-k} b^k
  • Properties:
    • The total number of terms in the expansion is n+1n+1.
    • Powers of aa decrease from nn to 00, while powers of bb increase from 00 to nn.
    • In each term, the sum of the powers of aa and bb equals nn.

Pascal's Triangle

  • Description: A triangular array of numbers where each number is the sum of the two directly above it.
  • Use: Provides the binomial coefficients for the expansion of (a+b)n(a + b)^n.
  • Example:
    • Row for n=4n=4: 1,4,6,4,11, 4, 6, 4, 1

Proof by Mathematical Induction for Binomial Theorem

  • Base Case: For n=1n=1, (a+b)1=a+b(a + b)^1 = a + b.
  • Inductive Step: Assume true for n=kn=k, prove for n=k+1n=k+1.
  • Conclusion: By induction, the theorem holds for all positive integers nn.

Binomial Coefficients

  • Notation: inom{n}{k}, also known as combinations.
  • Calculation: inom{n}{k} = \frac{n!}{k!(n-k)!}

Special Cases of Binomial Expansion

  • Negative Terms: (x−y)n=∑k=0n(−1)k(nk)xn−kyk(x - y)^n = \sum_{k=0}^{n} (-1)^k \binom{n}{k} x^{n-k} y^k
  • Example: (x−2y)5=x5−10x4y+40x3y2−80x2y3+80xy4−32y5(x - 2y)^5 = x^5 - 10x^4y + 40x^3y^2 - 80x^2y^3 + 80xy^4 - 32y^5

General Term and Middle Term

  • General Term: Tr+1=(nr)an−rbrT_{r+1} = \binom{n}{r} a^{n-r} b^r
  • Middle Term: If nn is even, middle term is Tn2+1T_{\frac{n}{2} + 1}; if odd, terms are Tn2T_{\frac{n}{2}} and Tn2+1T_{\frac{n}{2} + 1}.

Numerical Evaluation Using Binomial Theorem

  • Example: (98)5=(100−2)5(98)^5 = (100 - 2)^5
    • Expansion: =10000000000−5×100000000×2+10×1000000×4−10×10000×8+5×100×16−32= 10000000000 - 5 \times 100000000 \times 2 + 10 \times 1000000 \times 4 - 10 \times 10000 \times 8 + 5 \times 100 \times 16 - 32
    • Result: =9039207968= 9039207968

Binomial Identities and Divisibility Applications

  • Identity: inom{n}{0} + inom{n}{1} + inom{n}{2} + ext{...} + inom{n}{n} = 2^n
  • Divisibility: Prove 6n−5n6^n - 5n leaves remainder 1 when divided by 25.
    • Formula: 6n−5n=25k+16^n - 5n = 25k + 1
    • Conclusion: Remainder is 1.

Exercises

  • Expand: (1−2x)5(1 - 2x)^5, (2x+3)6(2x + 3)^6
  • Evaluate: (96)3(96)^3, (102)5(102)^5, (101)4(101)^4, (99)5(99)^5
  • Comparison: Determine which is larger, (1.1)10000(1.1)^{10000} or 10001000.
  • Divisibility Proof: Show 9n+1−8n−99^{n+1} - 8n - 9 is divisible by 64 for positive integers nn.
Do you belong in the Top 10%?

Our analytics show that most students struggle with specific concepts in Binomial Theorem. Take a free diagnostic test to generate your personal Learning DNA profile.

Practice Test – MCQs, True/False

Top

Multiple Choice Questions

A.

160

B.

240

C.

320

D.

180
Correct Answer: A

Solution:

The binomial expansion of (x+2)6(x + 2)^6 is given by: ∑k=06(6k)x6−k(2)k\sum_{k=0}^{6} \binom{6}{k} x^{6-k} (2)^k. The coefficient of the x3x^3 term is (63)×23=20×8=160\binom{6}{3} \times 2^3 = 20 \times 8 = 160.

Chapter Concept:

Numerical Evaluation Using Binomial Theorem

A.

a3+3a2b+3ab2+b3a^3 + 3a^2b + 3ab^2 + b^3

B.

a3+2a2b+ab2+b3a^3 + 2a^2b + ab^2 + b^3

C.

a3+3a2b+2ab2+b3a^3 + 3a^2b + 2ab^2 + b^3

D.

a3+3a2b+3ab2a^3 + 3a^2b + 3ab^2
Correct Answer: A

Solution:

The binomial expansion of (a+b)3(a + b)^3 is a3+3a2b+3ab2+b3a^3 + 3a^2b + 3ab^2 + b^3.

Chapter Concept:

Binomial Theorem for Positive Integral Indices

A.

10

B.

11

C.

12

D.

13
Correct Answer: B

Solution:

The sum of the coefficients in the expansion of (1+x)n(1 + x)^n is (1+1)n=2n(1 + 1)^n = 2^n. Given 2n=20482^n = 2048, solving gives n=11n = 11.

Chapter Concept:

General Term and Middle Term

A.

15

B.

30

C.

60

D.

120
Correct Answer: C

Solution:

The coefficient of the x4x^4 term in (x+2)6(x + 2)^6 is given by (64)(2)2=15×4=60\binom{6}{4}(2)^2 = 15 \times 4 = 60.

Chapter Concept:

Binomial Coefficients

A.

64

B.

128

C.

256

D.

512
Correct Answer: B

Solution:

The sum of the coefficients in the expansion of (a+b)n(a + b)^n is 2n2^n. For (a+b)7(a + b)^7, it is 27=1282^7 = 128.

Chapter Concept:

Pascal's Triangle

A.

2n2^n

B.

nn

C.

n+1n+1

D.

00
Correct Answer: A

Solution:

The sum of the coefficients in the expansion of (x+1)n(x + 1)^n is obtained by substituting x=1x = 1, which results in (1+1)n=2n(1 + 1)^n = 2^n.

Chapter Concept:

Binomial Identities and Divisibility Applications

A.

True

B.

False

C.

Depends on nn

D.

None of the above
Correct Answer: A

Solution:

Using the binomial theorem, 6n=(1+5)n=∑r=0n(nr)1n−r5r6^n = (1+5)^n = \sum_{r=0}^{n} \binom{n}{r} 1^{n-r} 5^r. Subtracting 5n5n and rearranging terms, we get 6n−5n=1+25k6^n - 5n = 1 + 25k, where kk is an integer, thus leaving a remainder of 1 when divided by 25.

Chapter Concept:

Binomial Identities and Divisibility Applications

A.

True, because 6n−5n=25k+16^n - 5n = 25k + 1 for some integer kk.

B.

False, because 6n−5n6^n - 5n is not divisible by 25.

C.

True, because 6n−5n=25k6^n - 5n = 25k for some integer kk.

D.

False, because 6n−5n6^n - 5n leaves a remainder of 0.
Correct Answer: A

Solution:

Using the binomial theorem, 6n−5n=25k+16^n - 5n = 25k + 1, thus leaving a remainder of 1.

Chapter Concept:

Binomial Identities and Divisibility Applications

A.

60x460x^4

B.

240x4240x^4

C.

160x4160x^4

D.

192x4192x^4
Correct Answer: A

Solution:

The expansion of (x+2)6(x + 2)^6 is given by ∑k=06(6k)x6−k2k\sum_{k=0}^{6} \binom{6}{k} x^{6-k} 2^k. The term containing x4x^4 corresponds to k=2k=2, which is (62)x422=60x4\binom{6}{2} x^4 2^2 = 60x^4.

Chapter Concept:

Proof by Mathematical Induction for Binomial Theorem

A.

m=n2m = \frac{n}{2}

B.

m=n+12m = \frac{n+1}{2}

C.

m=n−12m = \frac{n-1}{2}

D.

m=n+22m = \frac{n+2}{2}
Correct Answer: A

Solution:

When nn is even, the middle term in the expansion of (x+y)n(x + y)^n is the (n2+1)\left(\frac{n}{2} + 1\right)-th term, hence m=n2m = \frac{n}{2}.

Chapter Concept:

General Term and Middle Term

Experience the StudyTunnel Method

We do not just give you mock tests. We guide you through a gamified, AI-driven learning path designed to guarantee mastery.

Step 1: Practicing the Concepts

Binomial Theorem

Step 2: Master Boss Exam
Locked • Full Phase Assessment
Step 3: Redemption Arena
Locked • AI Weakness Tracker

True or False

Correct Answer: True

Solution:

For even nn, the expansion of (a+b)n(a + b)^n has a middle term at position n2+1\frac{n}{2}+1. This term is Tn2+1=(nn2)an2bn2T_{\frac{n}{2}+1} = \binom{n}{\frac{n}{2}} a^{\frac{n}{2}} b^{\frac{n}{2}}.

Chapter Concept :

General Term and Middle Term

Correct Answer: True

Solution:

In the expansion of (x−y)n(x - y)^n, the binomial coefficients alternate in sign due to the presence of (−y)(-y) raised to successive powers.

Chapter Concept :

Special Cases of Binomial Expansion

Correct Answer: True

Solution:

In the expansion of (a+b)n(a + b)^n, the sum of the indices of aa and bb in each term is equal to nn, as observed in the properties of the binomial expansion.

Chapter Concept :

Binomial Theorem for Positive Integral Indices

Correct Answer: True

Solution:

The general term in the binomial expansion of (a+b)n(a + b)^n is indeed given by Tr+1=(nr)an−rbrT_{r+1} = \binom{n}{r} a^{n-r} b^r, where (nr)\binom{n}{r} is the binomial coefficient.

Chapter Concept :

General Term and Middle Term

Correct Answer: True

Solution:

The proof of the binomial theorem for positive integers is obtained by applying the principle of mathematical induction.

Chapter Concept :

Proof by Mathematical Induction for Binomial Theorem

Correct Answer: True

Solution:

Pascal's Triangle is a triangular array of numbers where each number is the sum of the two directly above it. It is used to find binomial coefficients for the expansion of (a+b)n(a + b)^n.

Chapter Concept :

Pascal's Triangle

Correct Answer: True

Solution:

The binomial coefficients nCknC_k are the numbers in Pascal's triangle and can be used to write the row for any index without writing the earlier rows.

Chapter Concept :

Binomial Coefficients

Correct Answer: False

Solution:

In the expansion of (a+b)n(a + b)^n, the sum of the indices of aa and bb is nn in every term of the expansion.

Chapter Concept :

Pascal's Triangle

Correct Answer: False

Solution:

The middle term in the expansion of (a+b)n(a + b)^n is not necessarily the term with the highest coefficient. The middle term is determined by the position in the sequence, not by the coefficient size.

Chapter Concept :

General Term and Middle Term

Correct Answer: False

Solution:

While Pascal's triangle provides a convenient way to visualize the coefficients, they are mathematically derived using combinations, represented as nCknCk. The triangle itself is constructed based on these combinations.

Chapter Concept :

Binomial Coefficients

AI Learning Assistant
Top

I can help you understand Binomial Theorem better. Ask me anything!

Summarize the main points of Binomial Theorem.
What are the most important terms to remember here?
Explain this concept like I'm five.
Give me a quick 3-question practice quiz.
StudyTunnel Methodology

We dont just provide random mock tests. Our AI-driven, phase-wise learning system is designed to guarantee mastery from your first chapter to your final exam.

1
Master the Concepts

Start with chapter notes, formulas, and common exam mistakes. Practice with thousands of MCQs, True/False, and Descriptive questions with instant solutions.

2
Conquer Boss Exams

Once you master individual chapters, unlock Phase-wise Boss Exams. These milestone tests simulate the actual exam environment to test your retention across multiple subjects.

3
The Redemption Arena

The ultimate learning hack. Our AI tracks every mistake you make and dynamically generates custom tests targeting your weak points until you achieve 100% accuracy.