Question 1

A light ray travels from air into a medium with a refractive index of 1.5. If the angle of incidence is $30^\circ$, what is the angle of refraction in the medium?

Accepted Answer

Correct Option: A. Solution: Using Snell's Law: $n_1 \sin i = n_2 \sin r$, where $n_1 = 1$ (air), $n_2 = 1.5$, and $i = 30^\circ$. Solving for $r$, $\sin r = \frac{1}{1.5} 	imes \sin 30^\circ = \frac{1}{1.5} 	imes 0.5 = 0.333$. Thus, $r \approx 19.5^\circ$.

Question 2

A ray of light travels from air into glass with a refractive index of 1.50. If the speed of light in vacuum is $3 	imes 10^8 	ext{ m/s}$, what is the speed of light in the glass?

Accepted Answer

Correct Option: A. Solution: The speed of light in the glass is calculated using the formula $v = \frac{c}{n}$, where $c$ is the speed of light in vacuum and $n$ is the refractive index. Thus, $v = \frac{3 	imes 10^8}{1.50} = 2 	imes 10^8 	ext{ m/s}$.

Question 3

A spherical mirror and a thin spherical lens both have a focal length of -15 cm. What can be concluded about the nature of the mirror and the lens?

Accepted Answer

Correct Option: A. Solution: A negative focal length indicates that both the mirror and the lens are concave, as concave mirrors and lenses have negative focal lengths.

Question 4

What is the focal length of a lens with a power of $+2.0 	ext{ D}$?

Accepted Answer

Correct Option: A. Solution: The power of a lens $P$ is the reciprocal of its focal length $f$, given by $P = \frac{1}{f}$. Therefore, $f = \frac{1}{P} = \frac{1}{2.0} = 0.50 	ext{ m}$.

Question 5

A convex lens forms a real, inverted image of an object placed at twice its focal length. What is the size of the image relative to the object?

Accepted Answer

Correct Option: A. Solution: When an object is placed at twice the focal length of a convex lens, the image formed is real, inverted, and of the same size as the object, located at twice the focal length on the opposite side.

Question 6

What is the relationship between the radius of curvature $R$ and the focal length $f$ of a spherical mirror?

Accepted Answer

Correct Option: B. Solution: For spherical mirrors of small apertures, the radius of curvature is found to be equal to twice the focal length, i.e., $R = 2f$.

Question 7

A lens has a power of -2.5 dioptres. What type of lens is it and what is its focal length?

Accepted Answer

Correct Option: B. Solution: A negative power indicates a concave lens. The focal length is the reciprocal of the power: $f = \frac{1}{-2.5} = -0.4$ meters.

Question 8

Which of the following statements is true for the image formation by a concave mirror when the object is placed at the center of curvature?

Accepted Answer

Correct Option: B. Solution: When an object is placed at the center of curvature of a concave mirror, the image formed is real, inverted, and of the same size as the object.

Question 9

A convex mirror is used as a rear-view mirror in vehicles. If the radius of curvature of the mirror is 3 m, what is the focal length of the mirror?

Accepted Answer

Correct Option: C. Solution: The focal length $f$ of a spherical mirror is half the radius of curvature $R$. For a convex mirror, $f = -\frac{R}{2} = -\frac{3}{2} = -1.5$ m.

Question 10

A concave mirror forms an image of an object placed at a distance of 30 cm from the mirror. If the image is real, inverted, and twice the size of the object, what is the focal length of the mirror?

Accepted Answer

Correct Option: B. Solution: For a real, inverted image that is twice the size of the object, the image distance $v$ is -60 cm (since magnification $m = v/u = -2$, and $u = -30$ cm). Using the mirror formula $$\frac{1}{f} = \frac{1}{v} + \frac{1}{u}$$, we find $$\frac{1}{f} = \frac{1}{-60} + \frac{1}{-30} = -\frac{1}{20}$$. Thus, the focal length $f$ is 20 cm.

Question 11

A convex lens has a focal length of 10 cm. An object is placed 15 cm from the lens. Calculate the image distance and describe the nature of the image.

Accepted Answer

Correct Option: A. Solution: Using the lens formula $\frac{1}{v} - \frac{1}{u} = \frac{1}{f}$, with $u = -15$ cm and $f = 10$ cm, we find $v = 30$ cm. The image is real and inverted.

Question 12

A convex mirror is used as a rear-view mirror in vehicles. If the radius of curvature of the mirror is 2 m, what is the focal length of the mirror?

Accepted Answer

Correct Option: D. Solution: The focal length $f$ of a spherical mirror is given by $f = \frac{R}{2}$. For a convex mirror, $R = 2$ m, so $f = -\frac{2}{2} = -1$ m. The negative sign indicates the mirror is convex.

Question 13

A light ray enters a rectangular glass slab from air at an angle of incidence of $30^\circ$. If the refractive index of the glass is 1.5, what is the angle of refraction inside the glass?

Accepted Answer

Correct Option: A. Solution: Using Snell's law, $n_1 \sin i = n_2 \sin r$, where $n_1 = 1$ (air), $n_2 = 1.5$ (glass), and $i = 30^\circ$. Solving gives $r = \sin^{-1}(\frac{1}{1.5} 	imes \sin 30^\circ) = 19.47^\circ$.

Question 14

In a concave mirror, which of the following positions of an object will result in a virtual, erect, and enlarged image?

Accepted Answer

Correct Option: D. Solution: A concave mirror forms a virtual, erect, and enlarged image when the object is placed between the pole and the principal focus.

Question 15

A concave lens has a focal length of 15 cm. If an object is placed 30 cm from the lens, what is the position and nature of the image?

Accepted Answer

Correct Option: C. Solution: Using the lens formula $$\frac{1}{v} = \frac{1}{f} - \frac{1}{u}$$, we find $$v = -10$$ cm, indicating the image is on the same side as the object and is virtual and erect.

Question 16

Which of the following statements is true for a concave lens?

Accepted Answer

Correct Option: B. Solution: A concave lens always forms a virtual, erect, and diminished image regardless of the object's position.

Question 17

If a concave lens has a focal length of 15 cm, what is the power of the lens?

Accepted Answer

Correct Option: B. Solution: The power of a lens is given by the formula $P = \frac{1}{f}$, where $f$ is the focal length in meters. For a concave lens with $f = -15 	ext{ cm} = -0.15 	ext{ m}$, the power is $P = \frac{1}{-0.15} = -6.67 	ext{ D}$. However, the correct calculation should be $P = \frac{1}{-0.15} = -6.67 	ext{ D}$, but the correct option based on provided choices is $-1.5 	ext{ D}$, indicating a potential error in the options.

Question 18

What is the refractive index of a medium if the speed of light in that medium is $2 	imes 10^8 	ext{ m/s}$, given that the speed of light in vacuum is $3 	imes 10^8 	ext{ m/s}$?

Accepted Answer

Correct Option: C. Solution: The refractive index $n$ is given by the formula $n = \frac{c}{v}$, where $c$ is the speed of light in vacuum and $v$ is the speed of light in the medium. Thus, $n = \frac{3 	imes 10^8}{2 	imes 10^8} = 1.5$.

Question 19

A concave mirror forms a real, inverted image of an object placed at 10 cm in front of it. If the image is three times magnified, where is the image located?

Accepted Answer

Correct Option: B. Solution: The magnification $m$ is given by $m = -v/u$. Given $m = 3$ and $u = -10$ cm, we have $v = 3 	imes (-10) = -30$ cm. Thus, the image is located at 30 cm.

Question 20

A concave mirror has a focal length of 20 cm. If an object is placed at 60 cm from the mirror, where will the image be formed?

Accepted Answer

Correct Option: A. Solution: Using the mirror formula $$\frac{1}{f} = \frac{1}{v} + \frac{1}{u}$$, where $f = -20 	ext{ cm}$ and $u = -60 	ext{ cm}$, we find $v = -30 	ext{ cm}$. The image is formed at 30 cm on the same side as the object.

Question 21

According to Snell's Law, what is the relationship between the angle of incidence $i$ and the angle of refraction $r$ when light passes from one medium to another?

Accepted Answer

Correct Option: B. Solution: Snell's Law states that the ratio of the sine of the angle of incidence to the sine of the angle of refraction is a constant for a given pair of media.

Question 22

If a light ray travels from water (refractive index $1.33$) into kerosene (refractive index $1.44$), how does the light ray bend?

Accepted Answer

Correct Option: A. Solution: When light travels from a medium with a lower refractive index to a medium with a higher refractive index, it bends towards the normal.

Question 23

A convex lens forms an image of the same size as the object. Where should the object be placed?

Accepted Answer

Correct Option: B. Solution: For a convex lens to form an image of the same size as the object, the object must be placed at twice the focal length, which is at $2F_1$. The image will be real, inverted, and of the same size.

Question 24

A concave mirror has a focal length of 20 cm. An object is placed 60 cm from the mirror. Where will the image be formed, and what will be its nature?

Accepted Answer

Correct Option: A. Solution: Using the mirror formula $\frac{1}{v} + \frac{1}{u} = \frac{1}{f}$, with $u = -60$ cm and $f = -20$ cm, we find $v = -30$ cm. The image is real and inverted.

Question 25

Which of the following statements about the image formed by a convex mirror is correct?

Accepted Answer

Correct Option: B. Solution: A convex mirror always forms a virtual and erect image, regardless of the position of the object.

Question 26

A convex lens has a focal length of 20 cm. If an object is placed at a distance of 30 cm from the lens, what is the power of the lens in dioptres?

Accepted Answer

Correct Option: B. Solution: The power $P$ of a lens is given by $P = \frac{1}{f}$, where $f$ is the focal length in meters. Here, $f = 0.20$ m, so $P = \frac{1}{0.20} = 5.0$ D.

Question 27

A light ray passes through a rectangular glass slab and emerges parallel to the incident ray. What is the reason for this behavior?

Accepted Answer

Correct Option: C. Solution: The emergent ray is parallel to the incident ray because the extent of bending at the air-glass interface is equal and opposite to that at the glass-air interface, resulting in no net deviation.

Question 28

When light passes through a rectangular glass slab, what is the relationship between the incident ray and the emergent ray?

Accepted Answer

Correct Option: A. Solution: In a rectangular glass slab, the emergent ray is parallel to the incident ray due to equal and opposite bending at the two interfaces.

Question 29

A convex lens has a focal length of 15 cm. An object is placed at 10 cm from the lens. What is the nature of the image formed?

Accepted Answer

Correct Option: B. Solution: For a convex lens, when the object is placed between the focal point and the lens, the image formed is virtual, erect, and magnified.

Question 30

What is the principal focus of a concave mirror?

Accepted Answer

Correct Option: A. Solution: The principal focus of a concave mirror is the point where rays parallel to the principal axis converge after reflection.

Question 31

A spherical mirror has a radius of curvature of 20 cm. What is its focal length?

Accepted Answer

Correct Option: A. Solution: The focal length $f$ of a spherical mirror is half of its radius of curvature $R$. Therefore, $f = \frac{R}{2} = \frac{20}{2} = 10$ cm.

Question 32

What is the power of a lens with a focal length of 0.5 meters?

Accepted Answer

Correct Option: A. Solution: The power of a lens is the reciprocal of its focal length. Thus, $P = \frac{1}{f} = \frac{1}{0.5} = 2$ dioptres.

Question 33

A concave mirror has a radius of curvature of 20 cm. What is its focal length?

Accepted Answer

Correct Option: A. Solution: The focal length $f$ of a spherical mirror is half its radius of curvature $R$. Thus, $f = R/2 = 20/2 = 10$ cm.

Question 34

A convex lens is used to form a real and inverted image of an object. If the object is placed at a distance of 20 cm from the lens, and the image is formed at a distance of 40 cm on the opposite side, what is the focal length of the lens?

Accepted Answer

Correct Option: B. Solution: Using the lens formula $$\frac{1}{v} - \frac{1}{u} = \frac{1}{f}$$, where $v = 40$ cm and $u = -20$ cm. Substituting the values, we get $$\frac{1}{40} + \frac{1}{20} = \frac{1}{f}$$. Solving this gives $f = 13.33$ cm.

Question 35

A ray of light travels from air into a glass slab and then emerges back into air. If the angle of incidence is 30° and the refractive index of glass is 1.5, what is the angle of refraction inside the glass?

Accepted Answer

Correct Option: A. Solution: Using Snell's Law, $n_1 \sin i = n_2 \sin r$. For air to glass, $1 	imes \sin 30° = 1.5 	imes \sin r$. Solving gives $r = 19.47°$.

Question 36

In a refraction experiment, a light ray enters a rectangular glass slab at an angle of incidence of $30^\circ$. If the refractive index of the glass is 1.5, what is the angle of refraction inside the glass?

Accepted Answer

Correct Option: A. Solution: Using Snell's law, $n_1 \sin i = n_2 \sin r$, where $n_1 = 1$ (air), $n_2 = 1.5$ (glass), and $i = 30^\circ$. Solving gives $\sin r = \frac{1}{1.5} 	imes \sin 30^\circ = 0.333$. Thus, $r = \arcsin(0.333) \approx 19.47^\circ$.

Question 37

Which mirror can give an erect and enlarged image of an object?

Accepted Answer

Correct Option: A. Solution: A concave mirror can produce an erect and enlarged image when the object is placed between the pole and the principal focus.

Question 38

A concave lens has a focal length of $-20 	ext{ cm}$. What is the power of the lens?

Accepted Answer

Correct Option: B. Solution: The power $P$ of a lens is given by $P = \frac{1}{f}$, where $f$ is the focal length in meters. Thus, $P = \frac{1}{-0.2} = -5 	ext{ D}$.

Question 39

In a concave mirror, the centre of curvature lies in front of the mirror.

Accepted Answer

Answer: True. Solution: For a concave mirror, the centre of curvature is located in front of the mirror, as the reflecting surface curves inward towards the centre of the sphere.

Question 40

In a convex mirror, parallel rays of light appear to diverge from a point on the principal axis behind the mirror.

Accepted Answer

Answer: True. Solution: In a convex mirror, parallel rays appear to diverge from the principal focus located behind the mirror.

Question 41

The mirror formula for spherical mirrors is given by $$\frac{1}{v} + \frac{1}{u} = \frac{1}{f}$$, where $v$ is the image distance, $u$ is the object distance, and $f$ is the focal length.

Accepted Answer

Answer: False. Solution: The correct mirror formula is $$\frac{1}{v} + \frac{1}{u} = \frac{1}{f}$$, but the correct signs must be used according to the New Cartesian Sign Convention.

Question 42

Optical density and mass density are the same.

Accepted Answer

Answer: False. Solution: Optical density refers to the refractive index of a medium, which is not necessarily related to its mass density.

Question 43

The focal length of a spherical mirror is equal to half its radius of curvature.

Accepted Answer

Answer: True. Solution: For spherical mirrors of small apertures, the radius of curvature $R$ is found to be equal to twice the focal length $f$. Therefore, $f = \frac{R}{2}$.

Question 44

The power of a lens is defined as the reciprocal of its focal length.

Accepted Answer

Answer: True. Solution: The power of a lens is indeed defined as the reciprocal of its focal length, which is a measure of how strongly the lens converges or diverges light.

Question 45

In a concave mirror, the principal focus is located behind the mirror.

Accepted Answer

Answer: False. Solution: In a concave mirror, the principal focus is located in front of the mirror, as it converges light rays that are parallel to the principal axis.

Question 46

The mirror formula is given by $$\frac{1}{v} + \frac{1}{u} = \frac{1}{f}$$, where $v$ is the image distance, $u$ is the object distance, and $f$ is the focal length.

Accepted Answer

Answer: True. Solution: The mirror formula relates the object distance, image distance, and focal length of a spherical mirror.

Question 47

The principal focus of a concave mirror is located on the same side as the object.

Accepted Answer

Answer: True. Solution: For a concave mirror, the principal focus is indeed on the same side as the object, as the reflected rays converge at this point.

Question 48

According to Snell's Law, the ratio of the sine of the angle of incidence to the sine of the angle of refraction is constant for a given pair of media.

Accepted Answer

Answer: True. Solution: Snell's Law states that the ratio of the sine of the angle of incidence to the sine of the angle of refraction is a constant, known as the refractive index, for a given pair of media.

Question 49

According to Snell's Law, the ratio of the sine of the angle of incidence to the sine of the angle of refraction is constant for a given pair of media.

Accepted Answer

Answer: True. Solution: Snell's Law states that the ratio of the sine of the angle of incidence to the sine of the angle of refraction is a constant, which is the refractive index for the pair of media.

Question 50

When light passes through a rectangular glass slab, the emergent ray is parallel to the incident ray.

Accepted Answer

Answer: True. Solution: In a rectangular glass slab, refraction occurs at both the air-glass and glass-air interfaces. The emergent ray is parallel to the incident ray due to equal and opposite bending at the interfaces.

Question 51

The radius of curvature of a spherical mirror is equal to twice its focal length.

Accepted Answer

Answer: True. Solution: For spherical mirrors of small apertures, the radius of curvature $R$ is equal to twice the focal length $f$, i.e., $R = 2f$.

Question 52

In a concave mirror, the center of curvature lies behind the mirror.

Accepted Answer

Answer: False. Solution: For a concave mirror, the center of curvature lies in front of the mirror.

Question 53

Refraction of light occurs when light travels from one medium to another, changing its speed and direction.

Accepted Answer

Answer: True. Solution: Refraction is the bending of light as it passes from one medium to another due to a change in speed.

Question 54

When light passes through a rectangular glass slab, the emergent ray is parallel to the incident ray.

Accepted Answer

Answer: True. Solution: In the case of a rectangular glass slab, refraction occurs at both the air-glass and glass-air interfaces. The emergent ray is parallel to the incident ray due to equal and opposite bending at these interfaces.

Question 55

The focal length of a convex lens is negative, and it converges light rays to a point on the principal axis.

Accepted Answer

Answer: False. Solution: The focal length of a convex lens is positive, and it converges light rays to a point on the principal axis.

Question 56

A concave lens always forms a virtual, erect, and diminished image, irrespective of the position of the object.

Accepted Answer

Answer: True. Solution: A concave lens diverges light rays and always forms a virtual, erect, and diminished image, regardless of the object's position.

Question 57

The power of a lens is defined as the reciprocal of its focal length.

Accepted Answer

Answer: True. Solution: The power of a lens is indeed defined as the reciprocal of its focal length, which is a fundamental concept in optics.

Question 58

When light travels from a denser medium to a rarer medium, it bends towards the normal.

Accepted Answer

Answer: False. Solution: When light travels from a denser medium to a rarer medium, it bends away from the normal.

Question 59

For a spherical lens, the focal length is positive for a convex lens and negative for a concave lens.

Accepted Answer

Answer: True. Solution: According to the sign convention for spherical lenses, the focal length of a convex lens is positive, while that of a concave lens is negative.

Question 60

The refractive index is a measure of how much light slows down in a medium compared to vacuum.

Accepted Answer

Answer: True. Solution: The refractive index quantifies the reduction in speed of light as it passes through a medium compared to its speed in vacuum.

Question 61

A medium with a higher refractive index is always optically denser than a medium with a lower refractive index.

Accepted Answer

Answer: True. Solution: Optical density is determined by the refractive index; a medium with a higher refractive index is considered optically denser.

Question 62

The focal length of a spherical mirror is equal to half its radius of curvature.

Accepted Answer

Answer: True. Solution: For spherical mirrors, the focal length $f$ is indeed equal to half the radius of curvature $R$, i.e., $f = \frac{R}{2}$.

Question 63

For a spherical mirror, the focal length is equal to the radius of curvature.

Accepted Answer

Answer: False. Solution: The focal length of a spherical mirror is half the radius of curvature, given by $f = \frac{R}{2}$.

Question 64

The focal length of a convex lens is negative.

Accepted Answer

Answer: False. Solution: The focal length of a convex lens is positive because it converges light rays.

Position of Object	Position of Image	Size of Image	Nature of Image
At infinity	At focus F	Highly diminished, point-sized	Real and inverted
Beyond C	Between F and C	Diminished	Real and inverted
At C	At C	Same size	Real and inverted
Between C and F	Beyond C	Enlarged	Real and inverted
At F	At infinity	Image not formed
Between P and F	Behind the mirror	Enlarged	Virtual and erect

Material	Refractive Index
Air	1.0003
Water	1.33
Glass	1.52
Diamond	2.42

Position of Object	Position of Image	Relative Size	Nature
At infinity	At focus F2	Highly diminished	Real and inverted
Beyond 2F1	Between F2 and 2F2	Diminished	Real and inverted
At 2F1	At 2F2	Same size	Real and inverted
Between F1 and 2F1	Beyond 2F2	Enlarged	Real and inverted
At F1	At infinity	Image not formed
Between F1 and O	On the same side	Enlarged	Virtual and erect

Position of Object	Position of Image	Relative Size	Nature
At infinity	At focus F1	Highly diminished	Virtual and erect
Between infinity and O	Between F1 and O	Diminished	Virtual and erect

Light – Reflection and Re..

Learning Objectives

Learning Objectives

Revision Notes & Summary

Chapter Notes

Reflection of Light by Spherical Mirrors

Refraction of Light

Image Formation by Lenses

Mirror and Lens Formulas

Power of a Lens

Refractive Index and Optical Density

Exam Tips & Common Mistakes

Common Mistakes & Exam Tips

Reflection of Light by Spherical Mirrors

Refraction of Light

Image Formation by Lenses

Mirror and Lens Formulas

Power of a Lens

Refractive Index and Optical Density

Spherical Mirror Terminology and Sign Convention

Refraction through Rectangular Glass Slab

Spherical Lens Terminology and Sign Convention

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Multiple Choice Questions

Q1.A light ray travels from air into a medium with a refractive index of 1.5. If the angle of incidence is 30∘30^\circ30∘, what is the angle of refraction in the medium?

Correct Answer: A

Q2.A ray of light travels from air into glass with a refractive index of 1.50. If the speed of light in vacuum is 3×108 m/s3 \times 10^8 \text{ m/s}3×108 m/s, what is the speed of light in the glass?

Correct Answer: A

Q3.A spherical mirror and a thin spherical lens both have a focal length of -15 cm. What can be concluded about the nature of the mirror and the lens?

Correct Answer: A

Q4.What is the focal length of a lens with a power of +2.0 D+2.0 \text{ D}+2.0 D?

Correct Answer: A

Q5.A convex lens forms a real, inverted image of an object placed at twice its focal length. What is the size of the image relative to the object?

Correct Answer: A

Q6.What is the relationship between the radius of curvature RRR and the focal length fff of a spherical mirror?

Correct Answer: B

Q7.A lens has a power of -2.5 dioptres. What type of lens is it and what is its focal length?

Correct Answer: B

Q8.Which of the following statements is true for the image formation by a concave mirror when the object is placed at the center of curvature?

Correct Answer: B

Q9.A convex mirror is used as a rear-view mirror in vehicles. If the radius of curvature of the mirror is 3 m, what is the focal length of the mirror?

Correct Answer: C

Q10.A concave mirror forms an image of an object placed at a distance of 30 cm from the mirror. If the image is real, inverted, and twice the size of the object, what is the focal length of the mirror?

Correct Answer: B

Q11.A convex lens has a focal length of 10 cm. An object is placed 15 cm from the lens. Calculate the image distance and describe the nature of the image.

Correct Answer: A

Q12.A convex mirror is used as a rear-view mirror in vehicles. If the radius of curvature of the mirror is 2 m, what is the focal length of the mirror?

Correct Answer: D

Q13.A light ray enters a rectangular glass slab from air at an angle of incidence of 30∘30^\circ30∘. If the refractive index of the glass is 1.5, what is the angle of refraction inside the glass?

Correct Answer: A

Q14.In a concave mirror, which of the following positions of an object will result in a virtual, erect, and enlarged image?

Correct Answer: D

Q15.A concave lens has a focal length of 15 cm. If an object is placed 30 cm from the lens, what is the position and nature of the image?

Correct Answer: C

Q16.Which of the following statements is true for a concave lens?

Correct Answer: B

Q17.If a concave lens has a focal length of 15 cm, what is the power of the lens?

Correct Answer: B

Q18.What is the refractive index of a medium if the speed of light in that medium is 2×108 m/s2 \times 10^8 \text{ m/s}2×108 m/s, given that the speed of light in vacuum is 3×108 m/s3 \times 10^8 \text{ m/s}3×108 m/s?

Correct Answer: C

Q19.A concave mirror forms a real, inverted image of an object placed at 10 cm in front of it. If the image is three times magnified, where is the image located?

Correct Answer: B

Q20.A concave mirror has a focal length of 20 cm. If an object is placed at 60 cm from the mirror, where will the image be formed?

Correct Answer: A

Q21.According to Snell's Law, what is the relationship between the angle of incidence iii and the angle of refraction rrr when light passes from one medium to another?

Correct Answer: B

Q22.If a light ray travels from water (refractive index 1.331.331.33) into kerosene (refractive index 1.441.441.44), how does the light ray bend?

Correct Answer: A

Q23.A convex lens forms an image of the same size as the object. Where should the object be placed?

Correct Answer: B

Q24.A concave mirror has a focal length of 20 cm. An object is placed 60 cm from the mirror. Where will the image be formed, and what will be its nature?

Correct Answer: A

Q25.Which of the following statements about the image formed by a convex mirror is correct?

Correct Answer: B