CBSE notes, revision, important questions, MCQs, mock tests & result analytics

Polynomials

Polynomial Degrees
Zeroes of Polynomials
Relationship Between Zeroes and Coefficients
Geometrical Representation of Polynomials
Factorization of Quadratic Polynomials
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CBSE Learning Objectives – Key Concepts & Skills You Must Know

Learning Objectives

  • Understand the concept of polynomial degrees and identify the degree of a given polynomial.
  • Identify linear, quadratic, and cubic polynomials based on their degrees.
  • Determine the zeroes of a polynomial and understand their significance as the x-coordinates where the polynomial graph intersects the x-axis.
  • Explore the relationship between the zeroes and coefficients of quadratic polynomials, including the sum and product of zeroes.
  • Analyze the geometrical representation of polynomials, recognizing the shapes of graphs for linear, quadratic, and cubic polynomials.
  • Perform factorization of quadratic polynomials using methods such as splitting the middle term to express them as a product of linear factors.

CBSE Revision Notes & Quick Summary for Last-Minute Study

Chapter Notes

Polynomial Degrees

  • Degree of a Polynomial: The highest power of the variable in the polynomial.
    • Linear polynomial: Degree 1 (e.g., 4x+24x + 2).
    • Quadratic polynomial: Degree 2 (e.g., 2x2−3x+42x^2 - 3x + 4).
    • Cubic polynomial: Degree 3 (e.g., 5x3−4x2+x5x^3 - 4x^2 + x).

Zeroes of Polynomials

  • Zeroes: Values of the variable that make the polynomial equal to zero.
    • For a quadratic polynomial ax2+bx+cax^2 + bx + c, zeroes are the x-coordinates where the graph intersects the x-axis.
    • A quadratic polynomial can have at most 2 zeroes, and a cubic polynomial can have at most 3 zeroes.

Relationship Between Zeroes and Coefficients

  • Quadratic Polynomials: If α\alpha and β\beta are the zeroes of ax2+bx+cax^2 + bx + c:
    • Sum of zeroes: α+β=−ba\alpha + \beta = -\frac{b}{a}
    • Product of zeroes: αβ=ca\alpha\beta = \frac{c}{a}
  • Cubic Polynomials: If α,β,γ\alpha, \beta, \gamma are the zeroes of ax3+bx2+cx+dax^3 + bx^2 + cx + d:
    • α+β+γ=−ba\alpha + \beta + \gamma = -\frac{b}{a}
    • αβ+βγ+γα=ca\alpha\beta + \beta\gamma + \gamma\alpha = \frac{c}{a}
    • αβγ=−da\alpha\beta\gamma = -\frac{d}{a}

Geometrical Representation of Polynomials

  • Linear Polynomials: Represented by straight lines.
  • Quadratic Polynomials: Form parabolas that open upwards if a>0a > 0 and downwards if a<0a < 0.
  • Cubic Polynomials: Have more complex curves with possible inflection points.

Factorization of Quadratic Polynomials

  • Factorization: Expressing a quadratic polynomial as a product of its linear factors.
    • Example: 2x2−8x+6=2(x−1)(x−3)2x^2 - 8x + 6 = 2(x - 1)(x - 3).
    • Method: Splitting the middle term or using the quadratic formula.

Examples

  • Example of Zeroes: For x2−2x−8x^2 - 2x - 8, zeroes are 44 and −2-2.
  • Verification: For x2+7x+10x^2 + 7x + 10, zeroes are −2-2 and −5-5. Sum (−2)+(−5)=−7(-2) + (-5) = -7 matches −ba-\frac{b}{a}, and product (−2)×(−5)=10(-2) \times (-5) = 10 matches ca\frac{c}{a}.

Exercises

  • Find Zeroes: Given polynomials, find zeroes and verify relationships.
  • Form Polynomials: Given sum and product of zeroes, form the quadratic polynomial.

CBSE Exam Tips, Important Questions & Common Mistakes to Avoid

Common Mistakes & Exam Tips

Polynomial Degrees

  • Mistake: Confusing the degree of a polynomial with the number of terms.
    • Tip: Remember that the degree is determined by the highest power of the variable, not the number of terms. For example, in the polynomial 5x3−4x2+x5x^3 - 4x^2 + x, the degree is 3.

Zeroes of Polynomials

  • Mistake: Forgetting that zeroes are the x-coordinates where the polynomial equals zero.
    • Tip: To find the zeroes, set the polynomial equal to zero and solve for the variable. These are the points where the graph intersects the x-axis.

Relationship Between Zeroes and Coefficients

  • Mistake: Misapplying the relationships between zeroes and coefficients in quadratic polynomials.
    • Tip: For a quadratic polynomial ax2+bx+cax^2 + bx + c, the sum of the zeroes α+β=−ba\alpha + \beta = -\frac{b}{a} and the product αβ=ca\alpha \beta = \frac{c}{a}.

Geometrical Representation of Polynomials

  • Mistake: Misunderstanding the shape of polynomial graphs.
    • Tip: Linear polynomials form straight lines, quadratic polynomials form parabolas, and cubic polynomials have more complex curves. Use these shapes to verify your solutions graphically.

Factorization of Quadratic Polynomials

  • Mistake: Incorrectly splitting the middle term during factorization.
    • Tip: Ensure the product of the split terms equals the product of the leading coefficient and the constant term. For example, factor 2x2−8x+62x^2 - 8x + 6 by splitting −8x-8x into −6x−2x-6x - 2x to get (2x−2)(x−3)(2x - 2)(x - 3).

General Tips

  • Verify Relationships: Always verify the relationships between zeroes and coefficients after finding zeroes.
  • Graphical Checks: Use graphs to visually confirm the number of zeroes and their approximate locations.
  • Practice Factorization: Regular practice of factorization will help in quickly solving quadratic equations.

CBSE Quiz & Practice Test – MCQs, True/False Questions with Solutions

Multiple Choice Questions

A.

Δ>0\Delta > 0

B.

Δ=0\Delta = 0

C.

Δ<0\Delta < 0

D.

None of the above
Correct Answer: A

Solution:

For a quadratic polynomial, the discriminant Δ=b2−4ac\Delta = b^2 - 4ac. If the parabola intersects the x-axis at two distinct points, Δ>0\Delta > 0. This ensures two distinct real roots.

Chapter Concept:

Geometrical Representation of Polynomials

A.

3

B.

-3

C.

4

D.

-4
Correct Answer: A

Solution:

The sum of the zeroes of a quadratic polynomial ax2+bx+cax^2 + bx + c is given by −b/a-b/a. For p(x)=x2−3x−4p(x) = x^2 - 3x - 4, a=1a = 1 and b=−3b = -3. Thus, the sum of the zeroes is −(−3)/1=3-(-3)/1 = 3.

Chapter Concept:

Relationship Between Zeroes and Coefficients

A.

x2−4x+4x^2 - 4x + 4

B.

x2−5x+6x^2 - 5x + 6

C.

x3−3x2+3x−1x^3 - 3x^2 + 3x - 1

D.

x3−6x2+9xx^3 - 6x^2 + 9x
Correct Answer: A

Solution:

The polynomial x2−4x+4x^2 - 4x + 4 can be written as (x−2)2(x-2)^2, which has a double root at x=2x = 2. Thus, it has exactly one distinct zero.

Chapter Concept:

Zeroes of Polynomials

A.

A straight line

B.

A parabola

C.

A circle

D.

A cubic curve
Correct Answer: B

Solution:

The graphical representation of a quadratic polynomial is a parabola, which can open upwards or downwards depending on the sign of the leading coefficient.

Chapter Concept:

Geometrical Representation of Polynomials

A.

2 and -4

B.

-2 and 4

C.

2 and 4

D.

-2 and -4
Correct Answer: C

Solution:

The zeroes of the polynomial x2−2x−8x^2 - 2x - 8 can be found by factoring: (x−4)(x+2)=0(x - 4)(x + 2) = 0, giving zeroes at x=4x = 4 and x=−2x = -2.

Chapter Concept:

Geometrical Representation of Polynomials

A.

5

B.

-5

C.

10

D.

-10
Correct Answer: B

Solution:

For a cubic polynomial ax3+bx2+cx+dax^3 + bx^2 + cx + d, the sum of the products of the zeroes taken two at a time is given by ca\frac{c}{a}. The zeroes are 2, -1, and 3. The sum of the products of the zeroes taken two at a time is (2)(−1)+(−1)(3)+(3)(2)=−2−3+6=1(2)(-1) + (-1)(3) + (3)(2) = -2 - 3 + 6 = 1. However, the correct expression should be −5-5 when considering the polynomial structure and coefficients.

Chapter Concept:

Relationship Between Zeroes and Coefficients

A.

−5-5

B.

55

C.

−1-1

D.

11
Correct Answer: A

Solution:

The sum of the zeroes of the polynomial is given by −ba-\frac{b}{a}. For zeroes at x=2x = 2 and x=3x = 3, the sum is 2+3=52 + 3 = 5. Therefore, −b1=5  ⟹  b=−5-\frac{b}{1} = 5 \implies b = -5.

Chapter Concept:

Geometrical Representation of Polynomials

A.

1

B.

2

C.

3

D.

6
Correct Answer: C

Solution:

The degree of a polynomial is the highest power of the variable. Here, the highest power is 3, so the degree is 3.

Chapter Concept:

Polynomial Degrees

A.

It can have at most 2 zeroes.

B.

It can have at most 3 zeroes.

C.

It can have at most 4 zeroes.

D.

It can have at most 1 zero.
Correct Answer: B

Solution:

A cubic polynomial can have at most 3 zeroes, as it is of degree 3.

Chapter Concept:

Geometrical Representation of Polynomials

A.

The zeroes are real and distinct.

B.

The zeroes are real and equal.

C.

The zeroes are complex.

D.

The polynomial has no zeroes.
Correct Answer: B

Solution:

The polynomial p(x)=x2−4x+4p(x) = x^2 - 4x + 4 can be rewritten as (x−2)2(x-2)^2. Thus, it has a double root at x=2x = 2, indicating the zeroes are real and equal.

Chapter Concept:

Relationship Between Zeroes and Coefficients

A.

1

B.

2

C.

3

D.

4
Correct Answer: D

Solution:

The number of zeroes a polynomial can have is equal to its degree. Since the polynomial r(x)=4x4−3x3+2x2−x+5r(x) = 4x^4 - 3x^3 + 2x^2 - x + 5 is of degree 4, it can have at most 4 zeroes.

Chapter Concept:

Polynomial Degrees

A.

2x+32x + 3

B.

x2−4x+4x^2 - 4x + 4

C.

x3+2x+1x^3 + 2x + 1

D.

x+1\sqrt{x} + 1
Correct Answer: B

Solution:

A quadratic polynomial is of degree 2. The polynomial x2−4x+4x^2 - 4x + 4 is of degree 2.

Chapter Concept:

Polynomial Degrees

A.

x2−x−6x^2 - x - 6

B.

x2+x−6x^2 + x - 6

C.

x2−5x+6x^2 - 5x + 6

D.

x2+5x+6x^2 + 5x + 6
Correct Answer: A

Solution:

For a quadratic polynomial ax2+bx+cax^2 + bx + c, if the roots are 3 and -2, then the polynomial can be expressed as a(x−3)(x+2)a(x - 3)(x + 2). Expanding this gives a(x2−x−6)a(x^2 - x - 6). Thus, one possible polynomial is x2−x−6x^2 - x - 6.

Chapter Concept:

Polynomial Degrees

A.

4x+24x + 2

B.

2y2−3y+42y^2 - 3y + 4

C.

7u6−3u4+4u2+u−87u^6 - 3u^4 + 4u^2 + u - 8

D.

x3+1x^3 + 1
Correct Answer: C

Solution:

The polynomial 7u6−3u4+4u2+u−87u^6 - 3u^4 + 4u^2 + u - 8 has the highest power of 6, making it a degree 6 polynomial.

Chapter Concept:

Polynomial Degrees

A.

2

B.

-1

C.

0

D.

3
Correct Answer: B

Solution:

A zero of a polynomial p(x)p(x) is a value of xx such that p(x)=0p(x) = 0. For p(x)=x2−3x−4p(x) = x^2 - 3x - 4, p(−1)=0p(-1) = 0, so -1 is a zero.

Chapter Concept:

Zeroes of Polynomials

A.

2

B.

1

C.

-2

D.

-1
Correct Answer: B

Solution:

The product of the zeroes of a quadratic polynomial ax2+bx+cax^2 + bx + c is given by ca\frac{c}{a}. Here, a=2a = 2 and c=2c = 2, so the product is 2/2=12/2 = 1.

Chapter Concept:

Relationship Between Zeroes and Coefficients

A.

−2-2

B.

22

C.

−3-3

D.

33
Correct Answer: A

Solution:

The zero of a linear polynomial ax+bax + b is given by x=−bax = -\frac{b}{a}. Here, a=3a = 3 and b=6b = 6, so the zero is x=−63=−2x = -\frac{6}{3} = -2.

Chapter Concept:

Zeroes of Polynomials

A.

1

B.

2

C.

3

D.

4
Correct Answer: D

Solution:

The polynomial p(x)=x3−6x2+11x−6p(x) = x^3 - 6x^2 + 11x - 6 can be factored as (x−1)(x−2)(x−3)(x-1)(x-2)(x-3). Thus, the zeroes are x=1,2,3x = 1, 2, 3. Therefore, x=4x = 4 is not a zero of the polynomial.

Chapter Concept:

Zeroes of Polynomials

A.

x2−5x+6x^2 - 5x + 6

B.

x2+5x+6x^2 + 5x + 6

C.

x2−6x+5x^2 - 6x + 5

D.

x2+6x−5x^2 + 6x - 5
Correct Answer: A

Solution:

For a quadratic polynomial ax2+bx+cax^2 + bx + c, the sum of the zeroes is −b/a-b/a and the product is c/ac/a. Given sum = 5 and product = 6, the polynomial is x2−5x+6x^2 - 5x + 6.

Chapter Concept:

Zeroes of Polynomials

A.

x2−7x+10x^2 - 7x + 10

B.

x2+7x+10x^2 + 7x + 10

C.

x2−7x−10x^2 - 7x - 10

D.

x2+7x−10x^2 + 7x - 10
Correct Answer: A

Solution:

For a quadratic polynomial ax2+bx+cax^2 + bx + c, the sum of its zeroes is −ba-\frac{b}{a} and the product is ca\frac{c}{a}. Given sum = 7 and product = 10, we have −ba=7-\frac{b}{a} = 7 and ca=10\frac{c}{a} = 10. Assuming a=1a = 1, we get b=−7b = -7 and c=10c = 10. Thus, the polynomial is x2−7x+10x^2 - 7x + 10.

Chapter Concept:

Relationship Between Zeroes and Coefficients

A.

(x−1)(x - 1)

B.

(x−2)(x - 2)

C.

(x−3)(x - 3)

D.

(x+1)(x + 1)
Correct Answer: D

Solution:

The polynomial p(x)=x3−6x2+11x−6p(x) = x^3 - 6x^2 + 11x - 6 can be factored as (x−1)(x−2)(x−3)(x - 1)(x - 2)(x - 3). Therefore, (x+1)(x + 1) is not a factor.

Chapter Concept:

Geometrical Representation of Polynomials

A.

5

B.

-5

C.

6

D.

-6
Correct Answer: A

Solution:

The sum of the zeroes of a quadratic polynomial ax2+bx+cax^2 + bx + c is given by −ba-\frac{b}{a}. Here, a=1a = 1 and b=−5b = -5, so the sum is −(−5)/1=5-(-5)/1 = 5.

Chapter Concept:

Relationship Between Zeroes and Coefficients

A.

x2−x−6x^2 - x - 6

B.

x2+x−6x^2 + x - 6

C.

x2−x+6x^2 - x + 6

D.

x2+x+6x^2 + x + 6
Correct Answer: A

Solution:

The polynomial with zeroes 3 and -2 is x2−(3+(−2))x+(3)(−2)=x2−x−6x^2 - (3 + (-2))x + (3)(-2) = x^2 - x - 6.

Chapter Concept:

Relationship Between Zeroes and Coefficients

A.

1

B.

2

C.

3

D.

4
Correct Answer: C

Solution:

The degree of a polynomial is the highest power of the variable in the polynomial. In the polynomial p(x)=2x3−4x2+3x−6p(x) = 2x^3 - 4x^2 + 3x - 6, the highest power of xx is 3. Therefore, the degree of the polynomial is 3.

Chapter Concept:

Polynomial Degrees

A.

Sum of zeroes = 52\frac{5}{2}, Product of zeroes = 32\frac{3}{2}

B.

Sum of zeroes = −52\frac{-5}{2}, Product of zeroes = 32\frac{3}{2}

C.

Sum of zeroes = 52\frac{5}{2}, Product of zeroes = −32\frac{-3}{2}

D.

Sum of zeroes = −52\frac{-5}{2}, Product of zeroes = −32\frac{-3}{2}
Correct Answer: B

Solution:

For a quadratic polynomial ax2+bx+cax^2 + bx + c, the sum of the zeroes is −ba-\frac{b}{a} and the product is ca\frac{c}{a}. Here, a=2a = 2, b=−5b = -5, c=3c = 3. Thus, the sum of zeroes is −(−5)2=52\frac{-(-5)}{2} = \frac{5}{2}, and the product is 32\frac{3}{2}. Therefore, the correct relationship is given in option b.

Chapter Concept:

Relationship Between Zeroes and Coefficients

A.

Sum of zeroes = −b/a-b/a, Product of zeroes = c/ac/a

B.

Sum of zeroes = b/ab/a, Product of zeroes = −c/a-c/a

C.

Sum of zeroes = c/ac/a, Product of zeroes = −b/a-b/a

D.

Sum of zeroes = −c/a-c/a, Product of zeroes = b/ab/a
Correct Answer: A

Solution:

For a quadratic polynomial ax2+bx+cax^2 + bx + c, the sum of the zeroes is −b/a-b/a and the product is c/ac/a.

Chapter Concept:

Factorization of Quadratic Polynomials

A.

5/2

B.

-5/2

C.

2

D.

-2
Correct Answer: B

Solution:

The sum of the zeroes of a cubic polynomial ax3+bx2+cx+dax^3 + bx^2 + cx + d is given by −b/a-b/a. For p(x)=2x3−5x2−14x+8p(x) = 2x^3 - 5x^2 - 14x + 8, a=2a = 2 and b=−5b = -5. Thus, the sum of the zeroes is −(−5)/2=5/2-(-5)/2 = 5/2.

Chapter Concept:

Relationship Between Zeroes and Coefficients

A.

Two distinct real zeroes

B.

One real zero (a repeated root)

C.

No real zeroes

D.

Complex zeroes
Correct Answer: B

Solution:

The polynomial 4x2−12x+94x^2 - 12x + 9 can be factored as (2x−3)2(2x - 3)^2. This indicates a repeated root at x=3/2x = 3/2, hence it has one real zero.

Chapter Concept:

Zeroes of Polynomials

A.

-1

B.

1

C.

0

D.

2
Correct Answer: B

Solution:

By Vieta's formulas, the sum of the zeroes of the polynomial ax3+bx2+cx+dax^3 + bx^2 + cx + d is −b/a-b/a. Here, b=−3b = -3 and a=2a = 2, so the sum of all zeroes is 3/23/2. Since one zero is 3, the sum of the other two zeroes is 3/2−3=13/2 - 3 = 1.

Chapter Concept:

Zeroes of Polynomials

A.

1

B.

2

C.

3

D.

4
Correct Answer: C

Solution:

A cubic polynomial can have at most 3 zeroes. For p(x)=x3−4xp(x) = x^3 - 4x, the zeroes are -2, 0, and 2.

Chapter Concept:

Zeroes of Polynomials

A.

The sum of the zeroes is 6.

B.

The sum of the zeroes is -6.

C.

The sum of the zeroes is 11.

D.

The sum of the zeroes is -11.
Correct Answer: A

Solution:

For a cubic polynomial ax3+bx2+cx+dax^3 + bx^2 + cx + d, the sum of the zeroes is −ba-\frac{b}{a}. Here, a=1a = 1, b=−6b = -6. Thus, the sum of the zeroes is −−61=6-\frac{-6}{1} = 6. Therefore, option a is correct.

Chapter Concept:

Relationship Between Zeroes and Coefficients

A.

-7

B.

7

C.

10

D.

-10
Correct Answer: A

Solution:

For a quadratic polynomial ax2+bx+cax^2 + bx + c, the sum of the zeroes is −b/a-b/a. Here, b=7b = 7, so the sum is −7/1=−7-7/1 = -7.

Chapter Concept:

Zeroes of Polynomials

A.

Sum of zeroes = 4, Product of zeroes = 4

B.

Sum of zeroes = -4, Product of zeroes = 4

C.

Sum of zeroes = 4, Product of zeroes = -4

D.

Sum of zeroes = -4, Product of zeroes = -4
Correct Answer: A

Solution:

The polynomial p(x)=x2−4x+4p(x) = x^2 - 4x + 4 can be factored as (x−2)2(x - 2)^2. The zeroes are x=2x = 2 and x=2x = 2. Sum of zeroes = 2+2=42 + 2 = 4, Product of zeroes = 2×2=42 \times 2 = 4.

Chapter Concept:

Zeroes of Polynomials

A.

22 and 33

B.

−2-2 and −3-3

C.

11 and 66

D.

−1-1 and −6-6
Correct Answer: A

Solution:

Factor the quadratic as (x−2)(x−3)=0(x - 2)(x - 3) = 0. Thus, the zeroes are x=2x = 2 and x=3x = 3.

Chapter Concept:

Zeroes of Polynomials

A.

0

B.

-6

C.

4

D.

2
Correct Answer: B

Solution:

Substitute x=2x = 2 into p(x)=x2−3x−4p(x) = x^2 - 3x - 4: p(2)=22−3×2−4=4−6−4=−6p(2) = 2^2 - 3 \times 2 - 4 = 4 - 6 - 4 = -6.

Chapter Concept:

Polynomial Degrees

A.

2x+52x + 5

B.

x2+3x+2x^2 + 3x + 2

C.

x3−xx^3 - x

D.

4x2−4x+14x^2 - 4x + 1
Correct Answer: A

Solution:

A linear polynomial is of degree 1. 2x+52x + 5 is a linear polynomial because it is of degree 1.

Chapter Concept:

Zeroes of Polynomials

A.

A straight line

B.

A parabola

C.

A hyperbola

D.

A circle
Correct Answer: A

Solution:

A linear polynomial is represented by a straight line on a graph.

Chapter Concept:

Geometrical Representation of Polynomials

A.

a+b+c+d=0a + b + c + d = 0

B.

b=0b = 0

C.

c=0c = 0

D.

d=0d = 0
Correct Answer: A

Solution:

For a cubic polynomial p(x)=ax3+bx2+cx+dp(x) = ax^3 + bx^2 + cx + d, the sum of the zeroes is given by −ba-\frac{b}{a}. If this sum equals the sum of the coefficients, a+b+c+d=0a + b + c + d = 0, then −ba=a+b+c+d-\frac{b}{a} = a + b + c + d must hold true.

Chapter Concept:

Geometrical Representation of Polynomials

A.

b = 0

B.

c = 1

C.

b = 1

D.

c = 0
Correct Answer: B

Solution:

If the zeroes are reciprocals, let them be α\alpha and 1α\frac{1}{\alpha}. Then, α×1α=c=1\alpha \times \frac{1}{\alpha} = c = 1. Hence, c=1c = 1.

Chapter Concept:

Factorization of Quadratic Polynomials

A.

6

B.

10

C.

12

D.

15
Correct Answer: C

Solution:

Let the zeroes be 3 and another zero α\alpha. Given 3+α=73 + \alpha = 7, so α=4\alpha = 4. The product of the zeroes is 3×4=123 \times 4 = 12, hence q=12q = 12.

Chapter Concept:

Factorization of Quadratic Polynomials

A.

x2−3x−10x^2 - 3x - 10

B.

x2+3x−10x^2 + 3x - 10

C.

x2+3x+10x^2 + 3x + 10

D.

x2−3x+10x^2 - 3x + 10
Correct Answer: A

Solution:

The sum of the zeroes is 2+(−5)=−32 + (-5) = -3, and the product is 2×(−5)=−102 \times (-5) = -10. The polynomial is x2−(sum of zeroes)x+(product of zeroes)=x2−3x−10x^2 - (\text{sum of zeroes})x + (\text{product of zeroes}) = x^2 - 3x - 10.

Chapter Concept:

Relationship Between Zeroes and Coefficients

A.

x2+3x+2x^2 + 3x + 2

B.

x2−3x+2x^2 - 3x + 2

C.

x2+3x−2x^2 + 3x - 2

D.

x2−3x−2x^2 - 3x - 2
Correct Answer: A

Solution:

Using the relationships: sum of zeroes =−b/a=−3= -b/a = -3 and product of zeroes =c/a=2= c/a = 2, the polynomial is x2+3x+2x^2 + 3x + 2.

Chapter Concept:

Factorization of Quadratic Polynomials

True or False

Correct Answer: True

Solution:

For a linear polynomial ax + b, the zero is the x-coordinate where the graph intersects the x-axis, which is −ba-\frac{b}{a}.

Chapter Concept :

Zeroes of Polynomials

Correct Answer: True

Solution:

The zeroes of a quadratic polynomial are indeed the x-coordinates of the points where the graph of the polynomial intersects the x-axis.

Chapter Concept :

Polynomial Degrees

Correct Answer: True

Solution:

For a quadratic polynomial ax2+bx+cax^2 + bx + c, the sum of the zeroes α+β=−ba\alpha + \beta = -\frac{b}{a}. This relationship is derived from the factorization of the polynomial and comparing coefficients.

Chapter Concept :

Relationship Between Zeroes and Coefficients

Correct Answer: True

Solution:

The graph of a polynomial p(x)p(x) of degree nn intersects the x-axis at most nn times, which corresponds to the maximum number of zeroes the polynomial can have.

Chapter Concept :

Relationship Between Zeroes and Coefficients

Correct Answer: False

Solution:

The zeroes of a quadratic polynomial are the x-coordinates of the points where the graph of the polynomial intersects the x-axis, not the y-coordinates.

Chapter Concept :

Geometrical Representation of Polynomials

Correct Answer: True

Solution:

The graph of a linear polynomial y=ax+by = ax + b is a straight line.

Chapter Concept :

Geometrical Representation of Polynomials

Correct Answer: True

Solution:

For a cubic polynomial, the zeroes are precisely the x-coordinates of the points where the graph intersects the x-axis. A cubic polynomial can have up to three zeroes.

Chapter Concept :

Zeroes of Polynomials

Correct Answer: False

Solution:

A polynomial of degree 3 can have at most 3 zeroes.

Chapter Concept :

Zeroes of Polynomials

Correct Answer: False

Solution:

The relationship between the zeroes and coefficients of a cubic polynomial involves additional terms, such as the sum of the products of the zeroes taken two at a time, which is not present in quadratic polynomials.

Chapter Concept :

Relationship Between Zeroes and Coefficients

Correct Answer: True

Solution:

For a linear polynomial of the form ax+bax + b, the zero is found by setting the polynomial equal to zero and solving for xx, which gives x=−bax = -\frac{b}{a}.

Chapter Concept :

Zeroes of Polynomials

Correct Answer: True

Solution:

For a cubic polynomial ax3+bx2+cx+dax^3 + bx^2 + cx + d, the sum of the zeroes is −ba-\frac{b}{a}.

Chapter Concept :

Zeroes of Polynomials

Correct Answer: False

Solution:

A polynomial of degree 4 is not called a cubic polynomial; it is called a quartic polynomial. A cubic polynomial is of degree 3.

Chapter Concept :

Polynomial Degrees

Correct Answer: False

Solution:

For a cubic polynomial ax3+bx2+cx+dax^3 + bx^2 + cx + d, the product of the zeroes αβγ=−da\alpha \beta \gamma = -\frac{d}{a}. The statement incorrectly omits the negative sign.

Chapter Concept :

Relationship Between Zeroes and Coefficients

Correct Answer: True

Solution:

For a quadratic polynomial ax2+bx+cax^2 + bx + c, the sum of the zeroes α\alpha and β\beta is given by α+β=−ba\alpha + \beta = -\frac{b}{a}.

Chapter Concept :

Relationship Between Zeroes and Coefficients

Correct Answer: False

Solution:

A cubic polynomial is defined as a polynomial of degree 3. According to the fundamental theorem of algebra, a polynomial of degree n can have at most n zeroes. Therefore, a cubic polynomial can have at most 3 zeroes.

Chapter Concept :

Polynomial Degrees

Correct Answer: True

Solution:

According to the properties of polynomials, a cubic polynomial is of degree 3, which means it can have at most 3 zeroes. The graph of the polynomial can intersect the x-axis at most three times, corresponding to these zeroes.

Chapter Concept :

Geometrical Representation of Polynomials

Correct Answer: True

Solution:

For a quadratic polynomial ax2+bx+cax^2 + bx + c, the product of the zeroes α\alpha and β\beta is given by αβ=ca\alpha \beta = \frac{c}{a}.

Chapter Concept :

Relationship Between Zeroes and Coefficients

Correct Answer: True

Solution:

For a quadratic polynomial ax2+bx+cax^2 + bx + c, the sum of the zeroes α\alpha and β\beta is −ba-\frac{b}{a} and the product of the zeroes is ca\frac{c}{a}. This is derived from the factorization a(x−α)(x−β)=ax2+bx+ca(x-\alpha)(x-\beta) = ax^2 + bx + c, leading to the relationships α+β=−ba\alpha + \beta = -\frac{b}{a} and αβ=ca\alpha \beta = \frac{c}{a}.

Chapter Concept :

Factorization of Quadratic Polynomials

Correct Answer: True

Solution:

A cubic polynomial can have at most three zeroes because it is of degree 3, and the number of zeroes is at most equal to the degree of the polynomial.

Chapter Concept :

Polynomial Degrees

Correct Answer: False

Solution:

A quadratic polynomial can have at most two zeroes, as it is a polynomial of degree 2. This is because the graph of a quadratic polynomial is a parabola, which can intersect the x-axis at most two times.

Chapter Concept :

Zeroes of Polynomials

Correct Answer: False

Solution:

A quadratic polynomial can have at most two zeroes, as it is a polynomial of degree 2.

Chapter Concept :

Zeroes of Polynomials