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Pair of Linear Equations in Two Variables

Pair of Linear Equations in Two Variables

Study Action Plan (Sorted by Difficulty)
Application of Linear Equations in Real-Life Problems
Accuracy: 45%
Total Attempted332
Total Correct149
Total Incorrect183
Difficulty Level:
High
Substitution Method for Pair of Linear Equations
Accuracy: 63%
Total Attempted468
Total Correct296
Total Incorrect172
Difficulty Level:
Medium
Elimination Method for Pair of Linear Equations
Accuracy: 67%
Total Attempted375
Total Correct252
Total Incorrect123
Difficulty Level:
Medium
Conditions for Consistency of Linear Equations
Accuracy: 70%
Total Attempted607
Total Correct424
Total Incorrect183
Difficulty Level:
Medium
Graphical Solution of Linear Equations
Accuracy: 72%
Total Attempted279
Total Correct202
Total Incorrect77
Difficulty Level:
Medium
Forming Pair of Linear Equations from Word Problems
Accuracy: 83%
Total Attempted328
Total Correct272
Total Incorrect56
Difficulty Level:
Low

Learning Objectives

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Learning Objectives

  • Understand the graphical representation of linear equations in two variables and identify conditions for unique, infinite, or no solutions based on line intersections, parallelism, or coincidence.
  • Calculate solutions of linear equations using algebraic methods such as substitution and elimination, and determine conditions for consistency and dependency.
  • Analyze the coefficients of linear equations to assess the consistency, inconsistency, or dependency of the system using ratios of coefficients.
  • Apply linear equations to solve real-life problems, including age-related problems, cost calculations, and geometric problems, by formulating and solving pairs of linear equations.

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Revision Notes & Summary

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Chapter Notes

Graphical Solution of Linear Equations

  • Graphical Representation: A pair of linear equations in two variables can be represented graphically by two lines on a Cartesian plane.
  • Types of Solutions:
    • Unique Solution: The lines intersect at a single point. This indicates a consistent system.
    • No Solution: The lines are parallel and do not intersect. This indicates an inconsistent system.
    • Infinitely Many Solutions: The lines coincide, meaning every point on the line is a solution. This indicates a dependent and consistent system.
  • Example:
    • Equations: x+3y=6x + 3y = 6 and 2x−3y=122x - 3y = 12
    • Graphically, these lines intersect at (6,0)(6, 0), indicating a unique solution.

Algebraic Methods of Solving Linear Equations

  • Substitution Method:
    1. Solve one equation for one variable.
    2. Substitute this expression into the other equation.
    3. Solve the resulting equation for the second variable.
    4. Substitute back to find the first variable.
    • Example: Solve 7x−15y=27x - 15y = 2 and x+2y=3x + 2y = 3.
      • From x+2y=3x + 2y = 3, x=3−2yx = 3 - 2y.
      • Substitute in 7x−15y=27x - 15y = 2: 7(3−2y)−15y=27(3 - 2y) - 15y = 2.
      • Solve for yy: y=1929y = \frac{19}{29}.
      • Substitute back: x=4929x = \frac{49}{29}.
  • Elimination Method:
    1. Multiply equations to align coefficients of one variable.
    2. Add or subtract equations to eliminate one variable.
    3. Solve for the remaining variable.
    4. Substitute back to find the other variable.
    • Example: Solve 9x−4y=20009x - 4y = 2000 and 7x−3y=20007x - 3y = 2000.
      • Multiply to align yy: 27x−12y=600027x - 12y = 6000 and 28x−12y=800028x - 12y = 8000.
      • Subtract to eliminate yy: x=2000x = 2000.
      • Substitute back: y=4000y = 4000.

Conditions for Consistency of Linear Equations

  • Coefficient Ratios:
    • Consistent: a1a2≠b1b2\frac{a_1}{a_2} \neq \frac{b_1}{b_2}
    • Inconsistent: a1a2=b1b2≠c1c2\frac{a_1}{a_2} = \frac{b_1}{b_2} \neq \frac{c_1}{c_2}
    • Dependent: a1a2=b1b2=c1c2\frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2}

Application of Linear Equations in Real-Life Problems

  • Formulating Problems: Translate real-world situations into linear equations.
  • Example Problems:
    • Age Problem: Aftab's age problem can be represented by S−7=7(t−7)S - 7 = 7(t - 7) and S+3=3(t+3)S + 3 = 3(t + 3).
    • Cost Problem: The cost of pencils and erasers can be represented by 2x+3y=92x + 3y = 9 and 4x+6y=184x + 6y = 18.
  • Solution: Use algebraic methods to solve these equations and interpret the results in the context of the problem.
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Practice Test – MCQs, True/False

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Multiple Choice Questions

A.

The equations have a unique solution.

B.

The equations have no solution.

C.

The equations have infinitely many solutions.

D.

The equations have a solution at the origin.
Correct Answer: C

Solution:

Both equations represent the same line, hence they have infinitely many solutions.

Chapter Concept:

Elimination Method for Pair of Linear Equations

A.

The system has a unique solution.

B.

The system has no solution.

C.

The system has infinitely many solutions.

D.

The system is inconsistent.
Correct Answer: C

Solution:

The equations 2x+3y=92x + 3y = 9 and 4x+6y=184x + 6y = 18 are equivalent, meaning they represent the same line. Therefore, the system has infinitely many solutions.

Chapter Concept:

Forming Pair of Linear Equations from Word Problems

A.

x+2y=4x + 2y = 4 and 2x+4y=82x + 4y = 8

B.

x−2y=0x - 2y = 0 and 3x+4y=203x + 4y = 20

C.

2x+3y=92x + 3y = 9 and 4x+6y=184x + 6y = 18

D.

x+3y=6x + 3y = 6 and 2x−3y=122x - 3y = 12
Correct Answer: B

Solution:

Option b represents intersecting lines, hence a consistent pair with a unique solution.

Chapter Concept:

Forming Pair of Linear Equations from Word Problems

A.

2 rides

B.

3 rides

C.

4 rides

D.

5 rides
Correct Answer: B

Solution:

Let the number of rides be xx and the number of Hoopla games be yy. We have y=12xy = \frac{1}{2}x and 3x+4y=203x + 4y = 20. Solving these, x=3x = 3 rides.

Chapter Concept:

Application of Linear Equations in Real-Life Problems

A.

Substitute x=3−2yx = 3 - 2y into the second equation.

B.

Substitute y=3−x2y = \frac{3 - x}{2} into the first equation.

C.

Substitute y=27x+215y = \frac{2}{7}x + \frac{2}{15} into the first equation.

D.

Substitute x=7y+15x = 7y + 15 into the second equation.
Correct Answer: A

Solution:

Using the substitution method, solve for xx in the first equation: x=3−2yx = 3 - 2y. Substitute this expression for xx into the second equation to solve for yy.

Chapter Concept:

Substitution Method for Pair of Linear Equations

A.

2 rides

B.

3 rides

C.

4 rides

D.

5 rides
Correct Answer: B

Solution:

Let the number of rides be xx and the number of games be yy. We have y=12xy = \frac{1}{2}x and 3x+4y=203x + 4y = 20. Solving these equations, we get x=3x = 3 and y=1.5y = 1.5. Since yy must be an integer, x=3x = 3 is the only valid solution.

Chapter Concept:

Forming Pair of Linear Equations from Word Problems

A.

Intersecting lines

B.

Parallel lines

C.

Coincident lines

D.

None of the above
Correct Answer: C

Solution:

The equations represent coincident lines because they are scalar multiples of each other, indicating infinitely many solutions.

Chapter Concept:

Graphical Solution of Linear Equations

A.

1 pant

B.

2 pants

C.

3 pants

D.

4 pants
Correct Answer: A

Solution:

Let the number of pants be xx and skirts be yy. The equations are y=2x−2y = 2x - 2 and y=4x−4y = 4x - 4. Solving these gives x=1x = 1 pant.

Chapter Concept:

Application of Linear Equations in Real-Life Problems

A.

Unique solution

B.

No solution

C.

Infinitely many solutions

D.

Cannot be determined
Correct Answer: B

Solution:

The given equations are parallel lines since their slopes are equal and the constant terms differ, indicating no points of intersection. Thus, they have no solution.

Chapter Concept:

Graphical Solution of Linear Equations

A.

The lines intersect at a single point.

B.

The lines are parallel.

C.

The lines coincide.

D.

The lines form a triangle.
Correct Answer: B

Solution:

When the lines are parallel, they do not intersect, indicating that the pair of linear equations has no solution.

Chapter Concept:

Graphical Solution of Linear Equations

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Pair of Linear Equations in Two Variables

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True or False

Correct Answer: False

Solution:

A dependent pair of linear equations has infinitely many solutions, as the lines coincide.

Chapter Concept :

Conditions for Consistency of Linear Equations

Correct Answer: False

Solution:

The elimination method is sometimes more convenient than the substitution method, but not always. The convenience depends on the specific equations being solved.

Chapter Concept :

Elimination Method for Pair of Linear Equations

Correct Answer: True

Solution:

When two lines are coincident, every point on the line is a solution, leading to infinitely many solutions.

Chapter Concept :

Forming Pair of Linear Equations from Word Problems

Correct Answer: True

Solution:

When two lines coincide, every point on the line is a solution, resulting in infinitely many solutions. This is a dependent and consistent pair of equations.

Chapter Concept :

Forming Pair of Linear Equations from Word Problems

Correct Answer: True

Solution:

If the lines intersect at a single point, the pair of equations has a unique solution and is consistent.

Chapter Concept :

Conditions for Consistency of Linear Equations

Correct Answer: True

Solution:

In the elimination method, we multiply the equations by suitable constants to make the coefficients of one variable equal, allowing us to eliminate that variable.

Chapter Concept :

Elimination Method for Pair of Linear Equations

Correct Answer: True

Solution:

In the substitution method, one variable is expressed in terms of the other from one equation and substituted into the second equation to solve for the variables.

Chapter Concept :

Forming Pair of Linear Equations from Word Problems

Correct Answer: True

Solution:

Parallel lines represent an inconsistent pair of linear equations, meaning they do not intersect and thus have no solution.

Chapter Concept :

Graphical Solution of Linear Equations

Correct Answer: True

Solution:

When the elimination method results in a true statement with no variables, it indicates that the original pair of equations has infinitely many solutions.

Chapter Concept :

Elimination Method for Pair of Linear Equations

Correct Answer: False

Solution:

If a pair of linear equations is inconsistent, it means they have no solution. The elimination method cannot find a solution in such a case.

Chapter Concept :

Elimination Method for Pair of Linear Equations

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