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Arithmetic Progressions

Arithmetic Progressions

Study Action Plan (Sorted by Difficulty)
Sum-Based Equation Problems
Accuracy: 0%
Total Attempted0
Total Correct0
Total Incorrect0
Difficulty Level:
High
Finding Term Position (Which term = X)
Accuracy: 48%
Total Attempted23
Total Correct11
Total Incorrect12
Difficulty Level:
High
Applications of Arithmetic Progression in Real-Life Problems
Accuracy: 68%
Total Attempted117
Total Correct79
Total Incorrect38
Difficulty Level:
Medium
Nth Term of an Arithmetic Progression
Accuracy: 75%
Total Attempted32
Total Correct24
Total Incorrect8
Difficulty Level:
Low
Arithmetic Progression (AP)
Accuracy: 81%
Total Attempted340
Total Correct275
Total Incorrect65
Difficulty Level:
Low
Sum of First n Terms of an Arithmetic Progression
Accuracy: 87%
Total Attempted215
Total Correct187
Total Incorrect28
Difficulty Level:
Low
Determining Arithmetic Progression Characteristics
Accuracy: 90%
Total Attempted153
Total Correct138
Total Incorrect15
Difficulty Level:
Low
Finding Number of Terms (n)
Accuracy: 92%
Total Attempted189
Total Correct174
Total Incorrect15
Difficulty Level:
Low

Learning Objectives

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Learning Objectives

  • Understand the concept of Arithmetic Progression (AP) and identify sequences that form an AP by recognizing a constant difference between consecutive terms.
  • Calculate the Nth Term of an AP using the formula an=a+(n−1)⋅da_n = a + (n - 1) \cdot d, where aa is the first term, dd is the common difference, and nn is the term number.
  • Derive and apply the formula for the Sum of First n Terms of an AP, given by Sn=n2⋅[2a+(n−1)⋅d]S_n = \frac{n}{2} \cdot [2a + (n - 1) \cdot d] or Sn=n2⋅(a+l)S_n = \frac{n}{2} \cdot (a + l), where ll is the last term.
  • Determine the characteristics of a sequence to verify if it is an AP by checking the uniformity of the difference between consecutive terms.
  • Solve real-life problems using AP, such as calculating salary increments, savings schemes, and other scenarios involving uniform changes over time.

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Revision Notes & Summary

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Chapter Notes

Arithmetic Progression (AP)

  • Definition: An arithmetic progression is a sequence of numbers in which each term after the first is obtained by adding a constant difference to the preceding term.
  • General Form: a,a+d,a+2d,…a, a + d, a + 2d, \ldots
    • First Term (aa): The initial term of the sequence.
    • Common Difference (dd): The fixed number added to each term to get the next term.

Nth Term of an AP

  • Formula: The nth term of an arithmetic progression is given by: an=a+(n−1)⋅da_n = a + (n - 1) \cdot d
    • Where:
      • ana_n is the nth term.
      • aa is the first term.
      • dd is the common difference.
      • nn is the term number.

Sum of First n Terms of an AP

  • Formula: The sum of the first n terms of an arithmetic progression is calculated using: Sn=n2⋅[2a+(n−1)⋅d]S_n = \frac{n}{2} \cdot [2a + (n - 1) \cdot d]
    • Alternate Form: If the last term ll is known: Sn=n2⋅(a+l)S_n = \frac{n}{2} \cdot (a + l)
    • Where:
      • SnS_n is the sum of the first n terms.
      • aa is the first term.
      • dd is the common difference.
      • ll is the last term.
      • nn is the number of terms.

Determining AP Characteristics

  • Identification: A sequence is an AP if the difference between consecutive terms is constant.
  • Calculation: To determine if a sequence is an AP, calculate the difference between consecutive terms and check for consistency.

Applications of AP in Real-Life Problems

  • Salary Increments: Calculating future salaries with a constant annual increment.
  • Savings Schemes: Determining total savings over time with regular deposits.
  • Construction and Design: Calculating materials needed when dimensions increase or decrease uniformly.

Examples

  • Example 1: Calculate the 10th term of the AP: 2,7,12,…2, 7, 12, \ldots
    • Solution: a=2a = 2, d=5d = 5, n=10n = 10
    • a10=2+(10−1)⋅5=47a_{10} = 2 + (10 - 1) \cdot 5 = 47
  • Example 2: Find the sum of the first 22 terms of the AP: 8,3,−2,…8, 3, -2, \ldots
    • Solution: a=8a = 8, d=−5d = -5, n=22n = 22
    • S22=222⋅[2⋅8+(22−1)⋅(−5)]=−979S_{22} = \frac{22}{2} \cdot [2 \cdot 8 + (22 - 1) \cdot (-5)] = -979
These notes provide a structured overview of arithmetic progressions, focusing on their properties, formulas for the nth term and sum of terms, and practical applications in real-life scenarios.
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Practice Test – MCQs, True/False

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Multiple Choice Questions

A.

1, 4, 9, 16, ...

B.

2, 5, 8, 11, ...

C.

3, 6, 12, 24, ...

D.

5, 10, 20, 40, ...
Correct Answer: B

Solution:

The sequence 2, 5, 8, 11, ... has a constant difference of 3 between consecutive terms, thus it forms an AP.

Chapter Concept:

Determining Arithmetic Progression Characteristics

A.

30th term

B.

31st term

C.

32nd term

D.

33rd term
Correct Answer: B

Solution:

The nth term is given by an=121+(n−1)(−4)a_n = 121 + (n - 1)(-4). Setting an<0a_n < 0, we solve 121−4n+4<0121 - 4n + 4 < 0, giving n>31.25n > 31.25. Thus, the 32nd term is the first negative term.

Chapter Concept:

Nth Term of an Arithmetic Progression

A.

50th term

B.

51st term

C.

52nd term

D.

53rd term
Correct Answer: B

Solution:

Using the formula for the nth term of an AP, an=a+(n−1)da_n = a + (n-1)d, we have 301=5+(n−1)×6301 = 5 + (n-1) \times 6. Solving for nn, we get n=51n = 51. Therefore, the 51st term is 301301.

Chapter Concept:

Finding Term Position (Which term = X)

A.

31st

B.

32nd

C.

33rd

D.

34th
Correct Answer: B

Solution:

The nth term of an AP is an=a+(n−1)⋅da_n = a + (n-1) \cdot d. Here, a=121a = 121, d=−4d = -4. Setting an<0a_n < 0, we solve 121+(n−1)(−4)<0121 + (n-1)(-4) < 0 to find n=32n = 32.

Chapter Concept:

Finding Number of Terms (n)

A.

35 cm

B.

33 cm

C.

31 cm

D.

29 cm
Correct Answer: B

Solution:

The sequence of rung lengths is an arithmetic progression (AP) with first term a=45a = 45 cm and common difference d=−2d = -2 cm. The nth term is given by an=a+(n−1)⋅da_n = a + (n - 1) \cdot d. For the 6th rung, a6=45+(6−1)⋅(−2)=45−10=35a_6 = 45 + (6 - 1) \cdot (-2) = 45 - 10 = 35 cm.

Chapter Concept:

Determining Arithmetic Progression Characteristics

A.

150

B.

155

C.

160

D.

165
Correct Answer: A

Solution:

Using the formula Sn=n2[2a+(n−1)d]S_n = \frac{n}{2} [2a + (n - 1) d], we get S10=102[2(5)+(10−1)×3]=5×[10+27]=5×37=185S_{10} = \frac{10}{2} [2(5) + (10 - 1) \times 3] = 5 \times [10 + 27] = 5 \times 37 = 185.

Chapter Concept:

Sum of First n Terms of an Arithmetic Progression

A.

62

B.

61

C.

64

D.

65
Correct Answer: A

Solution:

The nth term of an AP is given by an=a+(n−1)da_n = a + (n - 1)d. Substituting the given values, a20=5+(20−1)×3=5+57=62a_{20} = 5 + (20 - 1) \times 3 = 5 + 57 = 62.

Chapter Concept:

Arithmetic Progression (AP)

A.

18

B.

20

C.

22

D.

24
Correct Answer: B

Solution:

The sum of the first nn terms of an AP is given by Sn=n2×(2a+(n−1)d)S_n = \frac{n}{2} \times (2a + (n-1)d). Substituting Sn=636S_n = 636, a=12a = 12, and d=3d = 3, we get 636=n2×(24+3(n−1))636 = \frac{n}{2} \times (24 + 3(n-1)). Solving this equation, we find n=20n = 20.

Chapter Concept:

Finding Number of Terms (n)

A.

₹12500

B.

₹13000

C.

₹13500

D.

₹14000
Correct Answer: B

Solution:

The salary for the nth year is given by an=a+(n−1)×da_n = a + (n-1) \times d. Here, a=8000a = 8000, d=500d = 500, and n=10n = 10. So, a10=8000+(10−1)×500=8000+4500=12500a_{10} = 8000 + (10-1) \times 500 = 8000 + 4500 = 12500.

Chapter Concept:

Applications of Arithmetic Progression in Real-Life Problems

A.

10

B.

11

C.

12

D.

13
Correct Answer: B

Solution:

The distance between the top and bottom rungs is 2.5 m or 250 cm. Since the rungs are 25 cm apart, the number of gaps between the rungs is 25025=10\frac{250}{25} = 10. Therefore, the number of rungs is 11.

Chapter Concept:

Nth Term of an Arithmetic Progression

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True or False

Correct Answer: False

Solution:

Using the formula Sn=n2[2a+(n−1)d]S_n = \frac{n}{2} [2a + (n - 1) d], we find S10=102[2×5+(10−1)×3]=5×[10+27]=5×37=185S_{10} = \frac{10}{2} [2 \times 5 + (10 - 1) \times 3] = 5 \times [10 + 27] = 5 \times 37 = 185. Therefore, the sum is 185, not 95.

Chapter Concept :

Sum of First n Terms of an Arithmetic Progression

Correct Answer: True

Solution:

In an arithmetic progression, if the common difference dd is zero, each term is obtained by adding zero to the previous term. Therefore, all terms in the sequence will be identical to the first term.

Chapter Concept :

Nth Term of an Arithmetic Progression

Correct Answer: True

Solution:

The formula an=a+(n−1)da_n = a + (n - 1) d correctly represents the nth term of an arithmetic progression.

Chapter Concept :

Arithmetic Progression (AP)

Correct Answer: False

Solution:

The sequence 1, 1, 2, 3, 5, 8 does not have a constant difference between consecutive terms, so it is not an arithmetic progression.

Chapter Concept :

Arithmetic Progression (AP)

Correct Answer: True

Solution:

An Arithmetic Progression (AP) is defined as a sequence where each term is obtained by adding a fixed number, known as the common difference, to the preceding term.

Chapter Concept :

Determining Arithmetic Progression Characteristics

Correct Answer: False

Solution:

The formula Sn=n2[2a+(n−1)d]S_n = \frac{n}{2} [2a + (n - 1) d] is valid for any common difference dd, whether positive, negative, or zero.

Chapter Concept :

Sum of First n Terms of an Arithmetic Progression

Correct Answer: True

Solution:

The formula an=a+(n−1)da_n = a + (n - 1) d is used to calculate the nth term of an arithmetic progression, where aa is the first term and dd is the common difference.

Chapter Concept :

Applications of Arithmetic Progression in Real-Life Problems

Correct Answer: True

Solution:

The formula Sn=n2(a+l)S_n = \frac{n}{2} (a + l) is applicable when the last term ll of the AP is known, as per the excerpt.

Chapter Concept :

Sum of First n Terms of an Arithmetic Progression

Correct Answer: True

Solution:

An arithmetic progression is defined as a sequence where each term after the first is obtained by adding a constant difference to the preceding term.

Chapter Concept :

Determining Arithmetic Progression Characteristics

Correct Answer: True

Solution:

The formula Sn=n2(a+l)S_n = \frac{n}{2} (a + l) is applicable when the last term ll of the finite AP is known, allowing for an alternative calculation of the sum.

Chapter Concept :

Sum of First n Terms of an Arithmetic Progression

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