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Molecular Basis of Inheritance

Molecular Basis of Inheritance

Action PlanNotesQuestionsMock-Test
Study Action Plan (Sorted by Difficulty)
Avery-MacLeod-McCarty Experiment
Accuracy: 0%
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High
Codon Table and Amino Acid Prediction
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High
DNA Fingerprinting
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High
HGP Methodologies
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High
Operon Concept
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Difficulty Level:
High
Polynucleotide Chain Structure
Accuracy: 0%
Total Attempted0
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Difficulty Level:
High
Template Strand and Coding Strand
Accuracy: 0%
Total Attempted0
Total Correct0
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Difficulty Level:
High
Replication Fork and DNA Polymerase
Accuracy: 0%
Total Attempted2
Total Correct0
Total Incorrect2
Difficulty Level:
High
RNA Processing in Eukaryotes
Accuracy: 38%
Total Attempted13
Total Correct5
Total Incorrect8
Difficulty Level:
High
Purines, Pyrimidines and Base Pairing
Accuracy: 40%
Total Attempted5
Total Correct2
Total Incorrect3
Difficulty Level:
High
Ribosome and Peptide Bond Formation
Accuracy: 45%
Total Attempted11
Total Correct5
Total Incorrect6
Difficulty Level:
High
Types of RNA
Accuracy: 46%
Total Attempted13
Total Correct6
Total Incorrect7
Difficulty Level:
High
Bacterial Transcription
Accuracy: 50%
Total Attempted10
Total Correct5
Total Incorrect5
Difficulty Level:
Medium
DNA as Genetic Material: Griffith Experiment
Accuracy: 50%
Total Attempted2
Total Correct1
Total Incorrect1
Difficulty Level:
Medium
Gene Regulation and Lac Operon
Accuracy: 50%
Total Attempted16
Total Correct8
Total Incorrect8
Difficulty Level:
Medium
Lac Operon Structural Genes
Accuracy: 50%
Total Attempted8
Total Correct4
Total Incorrect4
Difficulty Level:
Medium
Genetic Code and Translation
Accuracy: 52%
Total Attempted21
Total Correct11
Total Incorrect10
Difficulty Level:
Medium
DNA versus RNA as Genetic Material
Accuracy: 59%
Total Attempted22
Total Correct13
Total Incorrect9
Difficulty Level:
Medium
Hershey-Chase Experiment
Accuracy: 60%
Total Attempted5
Total Correct3
Total Incorrect2
Difficulty Level:
Medium
DNA Structure and Replication
Accuracy: 65%
Total Attempted20
Total Correct13
Total Incorrect7
Difficulty Level:
Medium
RNA and Transcription
Accuracy: 65%
Total Attempted20
Total Correct13
Total Incorrect7
Difficulty Level:
Medium
Eukaryotic RNA Polymerases
Accuracy: 67%
Total Attempted6
Total Correct4
Total Incorrect2
Difficulty Level:
Medium
Properties of Genetic Material
Accuracy: 67%
Total Attempted12
Total Correct8
Total Incorrect4
Difficulty Level:
Medium
Transcription Unit
Accuracy: 67%
Total Attempted3
Total Correct2
Total Incorrect1
Difficulty Level:
Medium
tRNA as Adapter Molecule
Accuracy: 67%
Total Attempted3
Total Correct2
Total Incorrect1
Difficulty Level:
Medium
VNTR and DNA Polymorphism
Accuracy: 67%
Total Attempted3
Total Correct2
Total Incorrect1
Difficulty Level:
Medium
Meselson-Stahl Experiment
Accuracy: 75%
Total Attempted4
Total Correct3
Total Incorrect1
Difficulty Level:
Low
Genetic Code Features
Accuracy: 78%
Total Attempted9
Total Correct7
Total Incorrect2
Difficulty Level:
Low
Central Dogma of Molecular Biology
Accuracy: 80%
Total Attempted15
Total Correct12
Total Incorrect3
Difficulty Level:
Low
Salient Features of DNA Double Helix
Accuracy: 86%
Total Attempted7
Total Correct6
Total Incorrect1
Difficulty Level:
Low
Chargaff’s Rule
Accuracy: 90%
Total Attempted10
Total Correct9
Total Incorrect1
Difficulty Level:
Low
Packaging of DNA
Accuracy: 90%
Total Attempted10
Total Correct9
Total Incorrect1
Difficulty Level:
Low
Semiconservative Replication
Accuracy: 90%
Total Attempted10
Total Correct9
Total Incorrect1
Difficulty Level:
Low
Mutations and Genetic Code
Accuracy: 95%
Total Attempted20
Total Correct19
Total Incorrect1
Difficulty Level:
Low
Exons, Introns and Split Genes
Accuracy: 100%
Total Attempted2
Total Correct2
Total Incorrect0
Difficulty Level:
Low
Leading and Lagging Strand Synthesis
Accuracy: 100%
Total Attempted4
Total Correct4
Total Incorrect0
Difficulty Level:
Low
Salient Features of Human Genome
Accuracy: 100%
Total Attempted6
Total Correct6
Total Incorrect0
Difficulty Level:
Low

Learning Objectives

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  • Understand the molecular basis of inheritance.
  • Explain the structure and function of DNA and RNA.
  • Describe the processes of DNA replication, transcription, and translation.
  • Analyze the role of ribosomes in protein synthesis.
  • Differentiate between various types of nucleic acids and their functions.
  • Discuss the significance of the Human Genome Project.
  • Explain the concept of DNA fingerprinting and its applications.
  • Understand the implications of mutations in genetic material.

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Revision Notes & Summary

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Molecular Basis of Inheritance

Exercises

  1. Group the following as nitrogenous bases and nucleosides:
    • Nitrogenous Bases: Adenine, Thymine, Guanine, Cytosine, Uracil
    • Nucleosides: Cytidine, Guanosine
  2. If a double stranded DNA has 20 percent of cytosine, calculate the percent of adenine in the DNA.
  3. If the sequence of one strand of DNA is written as follows:
    • 5'-ATGCATGCATGCATGCATGCATGCATGC-3'
    • Write down the sequence of complementary strand in 5'-3' direction.
  4. If the sequence of the coding strand in a transcription unit is written as follows:
    • 5'-ATGCATGCATGCATGCATGCATGCATGC-3'
    • Write down the sequence of mRNA.
  5. Which property of DNA double helix led Watson and Crick to hypothesise semi-conservative mode of DNA replication? Explain.
  6. Depending upon the chemical nature of the template (DNA or RNA) and the nature of nucleic acids synthesised from it (DNA or RNA), list the types of nucleic acid polymerases.
  7. How did Hershey and Chase differentiate between DNA and protein in their experiment while proving that DNA is the genetic material?
  8. Differentiate between the following:
    • (a) Repetitive DNA and Satellite DNA
    • (b) mRNA and tRNA
    • (c) Template strand and Coding strand
  9. List two essential roles of ribosome during translation.
  10. In the medium where E. coli was growing, lactose was added, which induced the lac operon. Then, why does lac operon shut down some time after addition of lactose in the medium?
  11. Explain (in one or two lines) the function of the following:
    • (a) Promoter
    • (b) tRNA
    • (c) Exons
  12. Why is the Human Genome project called a mega project?
  13. What is DNA fingerprinting? Mention its application.
  14. Briefly describe the following:
    • (a) Transcription
    • (b) Polymorphism
    • (c) Translation
    • (d) Bioinformatics
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Practice Test – MCQs, True/False

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Multiple Choice Questions

A.

Replication occurs continuously on both strands.

B.

Replication occurs continuously on the leading strand and discontinuously on the lagging strand.

C.

Replication occurs discontinuously on both strands.

D.

Replication occurs continuously on the lagging strand and discontinuously on the leading strand.
Correct Answer: B

Solution:

At the replication fork, the leading strand is synthesized continuously in the 5' to 3' direction, while the lagging strand is synthesized discontinuously in short fragments called Okazaki fragments.

Chapter Concept:

Replication Fork and DNA Polymerase

A.

It showed that proteins are the genetic material.

B.

It demonstrated that RNA is the genetic material.

C.

It identified DNA as the genetic material responsible for transformation.

D.

It proved that lipids are the genetic material.
Correct Answer: C

Solution:

The experiment by Avery, MacLeod, and McCarty showed that only DNA from heat-killed S cells could transform R cells into S cells, proving DNA is the genetic material.

Chapter Concept:

Avery-MacLeod-McCarty Experiment

A.

Promoter

B.

Structural gene

C.

Terminator

D.

Coding strand
Correct Answer: A

Solution:

The promoter is the DNA sequence that provides the binding site for RNA polymerase and helps define the coding/template strands.

Chapter Concept:

Transcription Unit

A.

Radioactive sulfur (35S^{35}S)

B.

Radioactive phosphorus (32P^{32}P)

C.

Radioactive carbon (14C^{14}C)

D.

Radioactive nitrogen (15N^{15}N)
Correct Answer: B

Solution:

Radioactive phosphorus (32P^{32}P) was used to label the DNA because DNA contains phosphorus but not sulfur.

Chapter Concept:

Hershey-Chase Experiment

A.

The genetic code is a triplet code, where each codon specifies one amino acid.

B.

The genetic code is non-degenerate, with each amino acid being coded by a single codon.

C.

The genetic code is different for prokaryotes and eukaryotes.

D.

The genetic code includes punctuation marks between codons.
Correct Answer: A

Solution:

The genetic code is a triplet code, meaning each codon consists of three nucleotides that specify a single amino acid. It is degenerate, meaning multiple codons can code for the same amino acid, and it is nearly universal across organisms.

Chapter Concept:

Genetic Code and Translation

A.

Cytosine

B.

Thymine

C.

Guanine

D.

Uracil
Correct Answer: B

Solution:

Chargaff's Rule states that in double-stranded DNA, the amount of adenine (AA) is equal to the amount of thymine (TT), and the amount of guanine (GG) is equal to the amount of cytosine (CC).

Chapter Concept:

Chargaff’s Rule

A.

5'-AUGCAUGCAUGC-3'

B.

5'-UACGUACGUACG-3'

C.

5'-GCAUGCAUGCAU-3'

D.

5'-CGUACGUACGUA-3'
Correct Answer: A

Solution:

The RNA sequence transcribed from the template strand (3'-ATGCATGCATGC-5') is 5'-AUGCAUGCAUGC-3', as RNA polymerase uses the template strand to synthesize RNA in the 5' to 3' direction, replacing thymine with uracil.

Chapter Concept:

Template Strand and Coding Strand

A.

UAA

B.

AUG

C.

UGA

D.

UAG
Correct Answer: B

Solution:

AUG is the start codon in the genetic code, which also codes for Methionine.

Chapter Concept:

Genetic Code and Translation

A.

DNA replication is conservative.

B.

DNA replication is semiconservative.

C.

DNA replication is dispersive.

D.

DNA replication is non-conservative.
Correct Answer: B

Solution:

The Meselson-Stahl experiment demonstrated that DNA replication is semiconservative, meaning each daughter DNA molecule consists of one parental and one newly synthesized strand.

Chapter Concept:

Meselson-Stahl Experiment

A.

Radioactive sulfur (35S^{35}S)

B.

Radioactive phosphorus (32P^{32}P)

C.

Radioactive carbon (14C^{14}C)

D.

Radioactive nitrogen (15N^{15}N)
Correct Answer: B

Solution:

The Hershey-Chase experiment used radioactive phosphorus (32P^{32}P) to label the DNA because DNA contains phosphorus but not sulfur.

Chapter Concept:

Hershey-Chase Experiment

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Molecular Basis of Inheritance

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True or False

Correct Answer: True

Solution:

The genetic code is nearly universal across all organisms, with very few exceptions such as mitochondrial codons and some protozoans.

Chapter Concept :

Genetic Code and Translation

Correct Answer: False

Solution:

In the Hershey-Chase experiment, radioactive phosphorus was used to label the DNA, while radioactive sulfur was used to label the protein of bacteriophages.

Chapter Concept :

Hershey-Chase Experiment

Correct Answer: True

Solution:

The Central Dogma describes the flow of genetic information in cells from DNA to RNA to protein. However, in some viruses, reverse transcription allows information to flow from RNA back to DNA.

Chapter Concept :

Central Dogma of Molecular Biology

Correct Answer: True

Solution:

The Avery-MacLeod-McCarty experiment showed that DNA from heat-killed S cells could transform R cells. Proteases and RNases did not stop the transformation, but DNase did, indicating that DNA is the transforming principle.

Chapter Concept :

Avery-MacLeod-McCarty Experiment

Correct Answer: True

Solution:

In eukaryotes, DNA is organized into nucleosomes, where the negatively charged DNA is wrapped around positively charged histone octamers. This structure is essential for DNA packaging and regulation.

Chapter Concept :

Packaging of DNA

Correct Answer: True

Solution:

Sickle cell anemia is caused by a point mutation in the beta globin gene, where a single base pair change results in the substitution of glutamate with valine.

Chapter Concept :

Mutations and Genetic Code

Correct Answer: True

Solution:

Chargaff's Rule states that in double-stranded DNA, the number of adenine bases equals the number of thymine bases and the number of guanine bases equals the number of cytosine bases. This purine-pyrimidine pairing keeps the DNA helix width nearly constant.

Chapter Concept :

Chargaff’s Rule

Correct Answer: True

Solution:

During transcription, only one of the two DNA strands is used as a template to synthesize RNA. This ensures that the RNA sequence is complementary to the DNA template strand.

Chapter Concept :

RNA and Transcription

Correct Answer: True

Solution:

In the DNA double helix, adenine forms two hydrogen bonds with thymine, which is a key feature of base pairing.

Chapter Concept :

Purines, Pyrimidines and Base Pairing

Correct Answer: True

Solution:

Nucleotides in a polynucleotide chain are linked through 3'-5' phosphodiester bonds, which connect the 3' hydroxyl group of one nucleotide's sugar to the 5' phosphate group of the next nucleotide.

Chapter Concept :

Polynucleotide Chain Structure

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