- Understand the dual nature of radiation and matter.
- Explain the photoelectric effect and its significance in physics.
- Calculate the work function and threshold frequency for various materials.
- Analyze the relationship between stopping potential and maximum kinetic energy of emitted electrons.
- Apply the concepts of Planck's constant and de Broglie wavelength in problem-solving.
Dual Nature of Radiation and Matter
Learning Objectives
TopRevision Notes & Summary
TopChapter 11: Dual Nature of Radiation and Matter
11.1 Introduction
- The wave nature of light was established through Maxwell's equations and Hertz's experiments.
- Key discoveries include X-rays by Roentgen (1895) and the electron by J.J. Thomson (1897).
- Discharge tubes showed that electric discharge through gases at low pressure could produce cathode rays.
11.2 Key Concepts
Physical Quantities
| Physical Quantity | Symbol | Dimensions | Unit | Remarks |
|---|---|---|---|---|
| Planck's constant | h | [ML²T⁻¹] | Js | E = hv |
| Stopping potential | V₀ | [ML²T⁻³A⁻¹] | V | eVo - Kmax |
| Work function | Ф₀ | [ML²T⁻²] | J; eV | Kₘₐₓ = E - Ф₀ |
| Threshold frequency | V₀ | [T⁻¹] | Hz | v = /h |
| de Broglie wavelength | A | [L] | m | A = h/p |
11.3 Points to Ponder
- Free electrons in metals move in a constant potential but require additional energy to escape.
- Electrons have a distribution of energies at a given temperature, differing from Maxwell's distribution due to Pauli's exclusion principle.
- The work function is the minimum energy required for an electron to escape the metal.
- Energy absorption during light-matter interaction occurs in discrete units of hv.
- The stopping potential's independence of intensity is crucial for distinguishing between wave and photon models of the photoelectric effect.
- The de Broglie wavelength has physical significance, while phase velocity does not; group velocity equals the particle's velocity.
11.4 Experimental Study of Photoelectric Effect
- Setup: An evacuated glass tube with a photosensitive plate and an anode.
- Process: Monochromatic light strikes the photosensitive plate, emitting electrons collected by the anode.
- Measurements: Current (μA) and potential difference (V) are monitored.
11.5 Observations on Photoelectric Effect
- Maximum kinetic energy of photoelectrons varies linearly with frequency, independent of intensity.
- No emission occurs below the threshold frequency, regardless of intensity.
- Emission starts instantaneously (~10⁻⁹ s) when frequency exceeds the threshold.
11.6 Examples
- Example 11.1: Photon energy and number of photons emitted by a laser.
- Example 11.2: Calculating threshold frequency and wavelength based on work function and stopping potential.
11.7 Exercises
- Calculate maximum kinetic energy and stopping potential for caesium with given frequency.
- Determine the threshold frequency and wavelength for various metals and light conditions.
Exam Tips & Common Mistakes
TopCommon Mistakes and Exam Tips
Common Pitfalls
- Misunderstanding the Photoelectric Effect: Students often confuse the concepts of intensity and frequency when discussing the photoelectric effect. Remember, the stopping potential is dependent on frequency, not intensity.
- Ignoring Work Function: Failing to account for the work function of the material when calculating the maximum kinetic energy of emitted electrons can lead to incorrect answers.
- Neglecting Threshold Frequency: Not recognizing that each material has a specific threshold frequency below which no photoelectrons are emitted can result in errors in predictions.
- Confusing Wavelength and Frequency: Students may mix up the relationships between wavelength, frequency, and energy. Always use the correct formulas to convert between these quantities.
Tips for Success
- Understand Key Concepts: Make sure to grasp the dual nature of light and matter, particularly how it relates to the photoelectric effect and de Broglie wavelength.
- Practice Calculations: Regularly practice problems involving the calculation of stopping potential, maximum kinetic energy, and the de Broglie wavelength to reinforce your understanding.
- Review Experimental Setups: Familiarize yourself with the experimental arrangements used to study the photoelectric effect, including the roles of the emitter and collector plates.
- Use Diagrams: When studying, draw diagrams to visualize concepts like the relationship between photoelectric current and collector plate potential, as well as the variation of photocurrent with intensity and frequency.
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Practice Test – MCQs, True/False
TopMultiple Choice Questions
A.
Electrons are emitted with reduced kinetic energy.
B.
No electrons are emitted from the photosensitive plate.
C.
The photocurrent increases.
D.
The potential difference across the circuit increases.
Correct Answer: B
Solution:
If the frequency of the incident light is below the threshold frequency, no electrons are emitted from the photosensitive plate, as the energy of the photons is insufficient to overcome the work function of the material.
A.
To emit electrons.
B.
To measure potential difference.
C.
To control light entry into the tube.
D.
To provide an external voltage source.
Correct Answer: C
Solution:
The guard window (S) controls the entry of light into the tube to ensure it strikes the photosensitive plate.
A.
Emits electrons when exposed to light
B.
Collects the emitted electrons
C.
Controls light entry into the tube
D.
Measures the current flow
Correct Answer: B
Solution:
The anode (A) is positioned on the right side within the tube and collects the emitted electrons.
A.
The kinetic energy of emitted electrons increases.
B.
The number of emitted electrons increases.
C.
The frequency of incident light increases.
D.
The threshold frequency of the photosensitive plate increases.
Correct Answer: B
Solution:
Increasing the intensity of light increases the number of photons striking the photosensitive plate, thereby increasing the number of emitted electrons.
A.
Potential difference
B.
Current flow due to electron movement
C.
Light intensity
D.
Voltage provided by the battery
Correct Answer: B
Solution:
The microammeter (μA) measures the current flow due to electron movement.
A.
To increase the frequency of light hitting the plate.
B.
To control the current flowing through the circuit.
C.
To measure the potential difference across the circuit.
D.
To emit electrons when exposed to light.
Correct Answer: B
Solution:
The resistor is included in the circuit to control the current, preventing excessive flow that could damage the components.
A.
To measure the potential difference
B.
To control the entry of light into the tube
C.
To provide an external voltage source
D.
To collect emitted electrons
Correct Answer: B
Solution:
The guard window is used to control the entry of light into the tube, ensuring it strikes the photosensitive plate accurately.
A.
To emit electrons
B.
To collect electrons
C.
To control light entry into the tube
D.
To measure potential difference
Correct Answer: C
Solution:
The guard window (S) controls the entry of light into the tube to ensure it strikes the photosensitive plate.
A.
To measure the voltage across the circuit.
B.
To measure the current due to electron flow.
C.
To regulate the intensity of the incident light.
D.
To control the potential difference applied.
Correct Answer: B
Solution:
The microammeter (μA) measures the current flow in the circuit, which is directly related to the number of electrons emitted and collected at the anode.
A.
Emits electrons when exposed to light
B.
Collects the emitted electrons
C.
Controls the current in the circuit
D.
Measures the potential difference
Correct Answer: B
Solution:
The anode (A) is positioned on the right side within the tube and collects the emitted electrons.
A.
The relationship between light frequency and electron emission
B.
The effect of light intensity on electron emission
C.
The change in photocurrent with different collector potentials
D.
The effect of temperature on electron flow
Correct Answer: C
Solution:
The variation of photocurrent with collector potential illustrates how the photocurrent changes with different collector potentials, as shown in the diagram.
A.
The photocurrent will increase.
B.
The photocurrent will decrease.
C.
The photocurrent will remain unchanged.
D.
The photocurrent will become zero.
Correct Answer: B
Solution:
A partially opaque guard window would reduce the intensity of light reaching the photosensitive plate, thereby decreasing the number of emitted electrons and reducing the photocurrent.
A.
Microammeter (μA)
B.
Voltmeter (V)
C.
Battery
D.
Resistor
Correct Answer: C
Solution:
The battery provides an external voltage source in the photoelectric effect setup.
A.
Voltmeter (V)
B.
Microammeter (μA)
C.
Battery
D.
Resistor
Correct Answer: B
Solution:
The microammeter (μA) measures the current flow due to electron movement.
A.
To measure the current flow due to electron movement.
B.
To control the light entry into the tube.
C.
To direct the circuit flow.
D.
To provide an external voltage source.
Correct Answer: C
Solution:
The commutator acts as a switch that directs the flow of the circuit, allowing for control over the experimental conditions.
A.
Voltmeter
B.
Microammeter
C.
Resistor
D.
Commutator
Correct Answer: C
Solution:
The resistor is included in the circuit to control the current.
A.
The kinetic energy of emitted electrons decreases.
B.
The photocurrent decreases.
C.
The number of emitted electrons increases.
D.
The stopping potential decreases.
Correct Answer: C
Solution:
Increasing the voltage across the anode and the photosensitive plate increases the electric field, which can enhance the collection of emitted electrons, thereby increasing the photocurrent.
A.
The number of emitted electrons doubles, increasing the photocurrent.
B.
The kinetic energy of the emitted electrons doubles.
C.
The threshold frequency of the material changes.
D.
The potential difference across the anode and photosensitive plate changes.
Correct Answer: A
Solution:
Doubling the intensity of light increases the number of photons striking the photosensitive plate, thus doubling the number of emitted electrons and increasing the photocurrent.
A.
Voltmeter (V)
B.
Microammeter (μA)
C.
Commutator
D.
Resistor
Correct Answer: B
Solution:
The microammeter (μA) measures the current flow due to electron movement in the experiment.
A.
Measures the voltage in the circuit
B.
Measures the current flow due to electron movement
C.
Provides an external voltage source
D.
Controls light entry into the tube
Correct Answer: B
Solution:
The microammeter (μA) measures the current flow due to electron movement in the circuit.
A.
The resistor.
B.
The microammeter.
C.
The battery.
D.
The commutator.
Correct Answer: C
Solution:
The battery provides the necessary external voltage required for the experiment, creating the potential difference across the anode and photosensitive plate.
A.
To emit electrons
B.
To collect electrons
C.
To control current
D.
To provide an external voltage source
Correct Answer: C
Solution:
The resistor is included in the circuit to control current.
A.
The kinetic energy of the emitted electrons increases.
B.
The number of electrons emitted increases.
C.
The frequency of the incident light increases.
D.
The threshold frequency of the material decreases.
Correct Answer: A
Solution:
Increasing the potential difference between the anode and the photosensitive plate accelerates the emitted electrons more, thereby increasing their kinetic energy.
A.
Microammeter
B.
Guard Window
C.
Commutator
D.
Resistor
Correct Answer: C
Solution:
The commutator is a switch that directs the circuit flow in the photoelectric effect setup.
A.
It emits electrons.
B.
It measures the current flow.
C.
It provides an external voltage source.
D.
It controls the current in the circuit.
Correct Answer: D
Solution:
The resistor is included in the circuit to control the current, ensuring it remains within safe limits.
A.
Photosensitive Plate
B.
Anode
C.
Resistor
D.
Guard Window
Correct Answer: C
Solution:
The resistor is included in the circuit to control the current, ensuring that the measurements are accurate and within safe limits.
A.
It measures the current flow due to electron movement.
B.
It controls the light entry into the tube.
C.
It directs the circuit flow, allowing reversal of current direction.
D.
It provides an external voltage source.
Correct Answer: C
Solution:
The commutator is a switch that directs the flow of the circuit, allowing the experimenter to reverse the current direction if needed.
A.
It emits electrons when exposed to light.
B.
It collects the emitted electrons.
C.
It controls the circuit flow.
D.
It measures the potential difference.
Correct Answer: B
Solution:
The anode (A) is positioned to collect the electrons emitted from the photosensitive plate.
A.
Voltmeter
B.
Microammeter
C.
Commutator
D.
Battery
Correct Answer: B
Solution:
The microammeter (μA) is used to measure the current flow due to the movement of electrons in the circuit.
A.
The current flow due to electron movement
B.
The potential difference in the circuit
C.
The light intensity striking the photosensitive plate
D.
The direction of the circuit flow
Correct Answer: B
Solution:
The voltmeter (V) monitors the potential difference in the circuit.
A.
Emits electrons when exposed to light
B.
Collects emitted electrons
C.
Controls light entry
D.
Measures current flow
Correct Answer: A
Solution:
The photosensitive plate (C) emits electrons when it is exposed to light, which is a key aspect of the photoelectric effect.
A.
To measure the potential difference across the circuit.
B.
To control the current in the circuit.
C.
To measure the current flow due to electron movement.
D.
To provide an external voltage source.
Correct Answer: C
Solution:
The microammeter is used to measure the current flow due to the movement of electrons from the photosensitive plate to the anode.
A.
To increase the frequency of incident light
B.
To control the current in the circuit
C.
To emit electrons from the photosensitive plate
D.
To measure the photocurrent
Correct Answer: B
Solution:
The resistor is included in the circuit to control the current, ensuring it remains within safe operational limits.
A.
It prevents electrons from escaping the glass tube.
B.
It controls the entry of light to the photosensitive plate.
C.
It measures the intensity of the incident light.
D.
It acts as a secondary anode to collect stray electrons.
Correct Answer: B
Solution:
The guard window (S) is used to control the amount of light entering the tube to ensure it strikes the photosensitive plate efficiently.
A.
To emit electrons when exposed to light.
B.
To collect emitted electrons.
C.
To control current in the circuit.
D.
To monitor the potential difference.
Correct Answer: C
Solution:
The resistor is included in the circuit to control current.
A.
The kinetic energy of the emitted electrons increases.
B.
The number of emitted electrons decreases.
C.
The current measured by the microammeter decreases.
D.
The light intensity on the photosensitive plate increases.
Correct Answer: C
Solution:
Decreasing the potential difference reduces the electric field strength, which may result in fewer electrons reaching the anode, thereby decreasing the current measured by the microammeter.
A.
To measure the potential difference in the circuit.
B.
To direct the circuit flow.
C.
To control the light intensity entering the tube.
D.
To provide an external voltage source.
Correct Answer: B
Solution:
The commutator is a switch that directs the circuit flow.
A.
Provides an external voltage source
B.
Measures the current flow due to electron movement
C.
Monitors the potential difference in the circuit
D.
Controls the circuit flow
Correct Answer: B
Solution:
The microammeter (μA) measures the current flow due to electron movement in the circuit.
A.
The microammeter will show a steady current.
B.
The microammeter will show fluctuating current readings.
C.
The microammeter will show zero current.
D.
The microammeter will show maximum current continuously.
Correct Answer: B
Solution:
A faulty commutator causing intermittent breaks in the circuit would lead to fluctuating current readings on the microammeter as the circuit is repeatedly opened and closed.
A.
To measure the current flow
B.
To provide an external voltage source
C.
To contain the experiment with labeled parts
D.
To control light entry into the tube
Correct Answer: C
Solution:
The evacuated glass tube contains the experiment with labeled parts.
A.
To emit electrons when exposed to light.
B.
To collect emitted electrons.
C.
To control light entry into the tube.
D.
To measure the current flow.
Correct Answer: C
Solution:
The guard window (S) controls light entry into the tube to strike the photosensitive plate.
A.
Stopping potential will increase.
B.
Stopping potential will decrease.
C.
Stopping potential will remain the same.
D.
Stopping potential will fluctuate.
Correct Answer: A
Solution:
Increasing the battery voltage increases the potential difference in the circuit, which in turn increases the stopping potential required to halt the emitted electrons.
A.
To maintain a vacuum for electron flow
B.
To amplify the light intensity
C.
To cool down the components
D.
To store excess electrons
Correct Answer: A
Solution:
The evacuated glass tube is used to maintain a vacuum, allowing electrons to flow freely from the photosensitive plate to the anode.
A.
The number of emitted electrons increases, leading to a higher photocurrent.
B.
The energy of each emitted electron increases.
C.
The threshold frequency of the material decreases.
D.
The potential difference across the circuit decreases.
Correct Answer: A
Solution:
Increasing the light intensity while keeping the frequency constant increases the number of photons striking the photosensitive plate. This results in more electrons being emitted, thereby increasing the photocurrent.
A.
Photosensitive plate (C)
B.
Anode (A)
C.
Guard window (S)
D.
Microammeter (μA)
Correct Answer: B
Solution:
The anode (A) is responsible for collecting the emitted electrons in the photoelectric effect experiment.
A.
It measures the current flow
B.
It provides an external voltage source
C.
It emits electrons when exposed to light
D.
It collects the emitted electrons
Correct Answer: B
Solution:
The battery provides an external voltage source necessary for the circuit in the photoelectric effect experiment.
A.
Electrons will be emitted with kinetic energy.
B.
No electrons will be emitted.
C.
Electrons will be emitted without any kinetic energy.
D.
The material will absorb the light without electron emission.
Correct Answer: A
Solution:
Since the frequency of the incident light ( Hz) is greater than the threshold frequency ( Hz), electrons will be emitted with kinetic energy.
A.
Photocurrent will increase.
B.
Photocurrent will decrease.
C.
Photocurrent will remain the same.
D.
Photocurrent will fluctuate randomly.
Correct Answer: A
Solution:
Increasing the intensity of light increases the number of photons striking the photosensitive plate, leading to an increase in the number of emitted electrons and thus increasing the photocurrent.
A.
Photosensitive Plate (C)
B.
Anode (A)
C.
Guard Window (S)
D.
Voltmeter (V)
Correct Answer: C
Solution:
The guard window (S) controls light entry into the tube to strike the photosensitive plate.
A.
Current flow
B.
Electron emission
C.
Potential difference
D.
Light intensity
Correct Answer: C
Solution:
The voltmeter (V) monitors the potential difference in the circuit during the photoelectric effect experiment.
A.
Photosensitive Plate (C)
B.
Voltmeter (V)
C.
Battery
D.
Resistor
Correct Answer: C
Solution:
The battery provides a constant external voltage source, maintaining a steady potential difference across the circuit.
A.
Measures the current flow
B.
Provides an external voltage source
C.
Emits electrons when exposed to light
D.
Controls light entry into the tube
Correct Answer: B
Solution:
The battery provides an external voltage source in the photoelectric effect setup.
A.
It would increase the photocurrent.
B.
It would decrease the photocurrent.
C.
It would have no effect on the photocurrent.
D.
It would increase the frequency of the emitted electrons.
Correct Answer: B
Solution:
Increasing the resistance in the circuit would reduce the current flow, thereby decreasing the photocurrent measured by the microammeter.
A.
Variation of photocurrent with different collector potentials and light intensities.
B.
The role of the anode in collecting electrons.
C.
The function of the microammeter in measuring current.
D.
The effect of the commutator on circuit flow.
Correct Answer: A
Solution:
The diagram likely illustrates the variation of photocurrent with different collector potentials and light intensities.
A.
Emits electrons when exposed to light
B.
Collects the emitted electrons
C.
Controls light entry into the tube
D.
Measures the current flow
Correct Answer: B
Solution:
The anode (A) is positioned on the right side within the tube and collects the emitted electrons.
A.
It measures the potential difference
B.
It controls the current
C.
It collects emitted electrons
D.
It emits electrons when exposed to light
Correct Answer: B
Solution:
The resistor is included in the circuit to control the current, ensuring it remains within safe limits.
A.
Measures the current flow
B.
Monitors the potential difference
C.
Directs the circuit flow
D.
Provides an external voltage source
Correct Answer: C
Solution:
The commutator is a switch that directs the circuit flow.
A.
To emit electrons when exposed to light.
B.
To collect emitted electrons.
C.
To control light entry into the tube.
D.
To measure the current flow.
Correct Answer: A
Solution:
The photosensitive plate (C) emits electrons when it is exposed to light, which is the fundamental principle of the photoelectric effect.
A.
Photosensitive Plate (C)
B.
Anode (A)
C.
Guard Window (S)
D.
Microammeter (μA)
Correct Answer: C
Solution:
The guard window (S) controls light entry into the tube to strike the photosensitive plate.
True or False
Correct Answer: True
Solution:
The diagram likely illustrates the photoelectric effect, showing how photocurrent changes with different collector potentials and light intensities.
Correct Answer: False
Solution:
The microammeter (μA) measures the current flow due to electron movement, whereas the voltmeter measures the potential difference.
Correct Answer: False
Solution:
The commutator is a switch that directs the circuit flow, but it does not specifically direct the flow of electrons from the anode to the photosensitive plate. Electrons flow from the photosensitive plate to the anode.
Correct Answer: False
Solution:
The voltmeter measures the potential difference in the circuit, not the current flow.
Correct Answer: True
Solution:
The diagram likely illustrates the variation of photocurrent with different collector potentials, as noted in the figure description.
Correct Answer: False
Solution:
The anode collects the emitted electrons, not emits them. The photosensitive plate is responsible for electron emission.
Correct Answer: False
Solution:
The commutator is a switch that directs the circuit flow, not a device for measuring current.
Correct Answer: True
Solution:
The battery supplies the necessary external voltage to the circuit in the photoelectric effect setup.
Correct Answer: True
Solution:
The battery is responsible for providing the external voltage necessary for the experiment.
Correct Answer: True
Solution:
According to the diagram description, the photosensitive plate is indeed located at the left side in the glass tube.
Correct Answer: False
Solution:
The microammeter measures the current flow due to electron movement, not the voltage.
Correct Answer: True
Solution:
The figure note on page 5 indicates that the diagram shows the variation of photocurrent with different collector potentials and light intensities.
Correct Answer: False
Solution:
The guard window controls light entry into the tube to strike the photosensitive plate, not the anode.
Correct Answer: True
Solution:
The diagram shows the variation of photocurrent with different collector potentials and light intensities.
Correct Answer: True
Solution:
The photosensitive plate (C) is specifically mentioned as emitting electrons when exposed to light, which is a key aspect of the photoelectric effect.
Correct Answer: True
Solution:
The commutator acts as a switch to direct the circuit flow, as mentioned in the setup description.
Correct Answer: True
Solution:
The photosensitive plate is designed to emit electrons when it is exposed to light, as part of the photoelectric effect.
Correct Answer: False
Solution:
The anode (A) is positioned on the right side within the tube, as indicated in the diagram description.
Correct Answer: False
Solution:
The commutator is a switch directing the circuit flow, not controlling light entry.
Correct Answer: True
Solution:
The anode is positioned on the right side within the tube and collects the emitted electrons.
Correct Answer: True
Solution:
The battery in the setup provides an external voltage source.
Correct Answer: True
Solution:
The anode is positioned on the right side within the tube and collects the emitted electrons.
Correct Answer: True
Solution:
The resistor is included in the circuit to control the current, as mentioned in the setup details.
Correct Answer: True
Solution:
The voltmeter is indeed used to monitor the potential difference across the circuit.
Correct Answer: True
Solution:
The photosensitive plate is designed to emit electrons when it is exposed to light, as described in the experimental setup.
Correct Answer: True
Solution:
The evacuated glass tube is described as containing the experiment with labeled parts.
Correct Answer: True
Solution:
The resistor is included in the circuit to control the current, as described in the setup.
Correct Answer: True
Solution:
The battery is included in the setup to provide an external voltage source.
Correct Answer: True
Solution:
The commutator acts as a switch to direct the flow of the circuit.
Correct Answer: True
Solution:
The photosensitive plate (C) is designed to emit electrons when it is exposed to light, as described in the diagram.
Correct Answer: False
Solution:
The commutator is a switch directing the circuit flow, not measuring current.
Correct Answer: False
Solution:
Electrons flow from the photosensitive plate to the anode, not the other way around.
Correct Answer: False
Solution:
The microammeter measures the current flow due to electron movement, not the potential difference.
Correct Answer: True
Solution:
The figure note on page 5 indicates that the diagram illustrates how photocurrent changes with varying collector potentials and light intensities.
Correct Answer: False
Solution:
The photosensitive plate is located on the left side of the evacuated glass tube.
Correct Answer: False
Solution:
The anode is positioned on the right side within the tube, as indicated in the diagram description.
Correct Answer: True
Solution:
The microammeter is used to measure the current flow resulting from the movement of electrons in the circuit.
Correct Answer: False
Solution:
The anode (A) is positioned to collect the electrons emitted by the photosensitive plate, not to emit them.
Correct Answer: False
Solution:
The anode is responsible for collecting the emitted electrons, not emitting them.
Correct Answer: False
Solution:
The voltmeter measures the potential difference in the circuit, not the current flow.
Correct Answer: False
Solution:
The resistor is included in the circuit to control current, not the potential difference.
Correct Answer: False
Solution:
The resistor is included in the circuit to control the current, not the voltage.
Correct Answer: True
Solution:
The voltmeter monitors the potential difference in the circuit, which includes the photosensitive plate and the anode.
Correct Answer: False
Solution:
The guard window (S) controls light entry into the tube, not electron entry.
Correct Answer: False
Solution:
The microammeter measures the current flow due to electron movement, not the potential difference.
Correct Answer: True
Solution:
The resistor is included in the circuit to control the current flow.
Correct Answer: True
Solution:
The battery provides the external voltage source required for the setup to function and for the study of the photoelectric effect.
Correct Answer: True
Solution:
The guard window is specifically designed to control the entry of light into the tube to strike the photosensitive plate.
Correct Answer: True
Solution:
The microammeter is used to measure the current flow resulting from electron movement in the circuit.
Correct Answer: False
Solution:
The photosensitive plate emits electrons when exposed to light, not collects them.
Correct Answer: True
Solution:
The guard window (S) is specifically mentioned as controlling the light entry into the tube to strike the photosensitive plate.
Correct Answer: True
Solution:
The diagram likely shows the variation of photocurrent with different light intensities.