• Learning Objectives:
  • Understand the concept of electrostatic potential and its relation to electric fields.
  • Calculate the electric potential due to point charges and charge distributions.
  • Analyze the behavior of capacitors in series and parallel configurations.
  • Apply the principles of electrostatics to solve problems involving capacitors and electric fields.
  • Explore the effects of dielectric materials on capacitance and electric fields.
  • Investigate the concept of electrostatic shielding and its applications.

Electrostatic Potential and Capacitance

Introduction

• The notion of potential energy was introduced in previous chapters, where work done against a force results in stored potential energy.
• Coulomb force between stationary charges is a conservative force, similar to gravitational force.

Key Concepts

• Electrostatic Shielding: A cavity inside a conductor is shielded from outside electrical influences, but charges inside the cavity do not shield the exterior.

Exercises

1. Electric Potential Zero: Two charges 5 X 10⁻⁸ C and -3 X 10⁻⁸ C are located 16 cm apart. Find points where electric potential is zero.
2. Hexagon Charge Potential: A regular hexagon with side 10 cm has a charge of 5 µC at each vertex. Calculate the potential at the center.
3. Equipotential Surface: Two charges 2 µC and -2 µC are placed 6 cm apart. Identify an equipotential surface and the direction of the electric field on this surface.
4. Spherical Conductor: A spherical conductor of radius 12 cm has a charge of 1.6 X 10⁻⁷C. Calculate the electric field inside, just outside, and at a point 18 cm from the center.
5. Capacitance Calculation: A parallel plate capacitor with air has a capacitance of 8 pF. Calculate capacitance if the distance is halved and filled with a dielectric constant of 6.
6. Series Capacitors: Three capacitors of 9 pF each are connected in series. Find total capacitance and potential difference across each capacitor connected to a 120 V supply.
7. Parallel Capacitors: Three capacitors of 2 pF, 3 pF, and 4 pF are connected in parallel. Find total capacitance and charge on each capacitor connected to a 100 V supply.
8. Capacitance of Parallel Plate: For a parallel plate capacitor with area 6 X 10⁻³ m² and distance 3 mm, calculate capacitance and charge when connected to a 100 V supply.

Important Formulas

• Capacitance: C = Q/V, where Q is charge and V is potential difference.
• Capacitance in Series: $\frac{1}{C} = \frac{1}{C_1} + \frac{1}{C_2} + \frac{1}{C_3} + \cdots$
• Capacitance in Parallel: C = C₁ + C₂ + C₃ + ...
• Energy Stored in Capacitor: U = $\frac{1}{2} C V^2$
• Electric Field in Dielectric: E = E₀/K, where K is the dielectric constant.

Points to Ponder

1. Electrostatics deals with forces between charges at rest, maintained by unspecified opposing forces.
2. A capacitor confines electric field lines, resulting in a small potential difference despite strong fields.
3. Electric field is zero inside a charged spherical shell, while potential is continuous across the surface.
4. The torque on a dipole in an electric field causes oscillation, aligning with the field if damped.
5. Potential due to a charge at its own location is infinite.