CBSE notes, revision, important questions, MCQs, mock tests & result analytics

Circles

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CBSE Learning Objectives – Key Concepts & Skills You Must Know

  • Understand the properties of angles and chords in circles.
  • Apply theorems related to cyclic quadrilaterals and angles subtended by chords.
  • Prove relationships between angles subtended by arcs at different points.
  • Analyze the properties of equal chords and their corresponding angles at the center.
  • Explore the concept of cyclic quadrilaterals and their angle properties.
  • Demonstrate the relationship between the angles subtended by arcs and their corresponding chords.

CBSE Revision Notes & Quick Summary for Last-Minute Study

Chapter 9: Circles

9.1 Angle Subtended by a Chord at a Point

  • A line segment PQ and a point R not on the line containing PQ.
  • Angle PRQ is called the angle subtended by the line segment PQ at point R.
  • Angles POQ, PRQ, and PSQ are defined as follows:
    • POQ: angle subtended by the chord PQ at the center O.
    • PRQ: angle subtended by PQ at point R.
    • PSQ: angle subtended by PQ at point S on the major arc PQ.

9.2 Properties of Angles in Circles

  1. Angle in a semicircle: The angle subtended by a diameter at any point on the circle is a right angle.
  2. Cyclic Quadrilaterals: The sum of either pair of opposite angles of a cyclic quadrilateral is 180°.
  3. Equal Chords: Equal chords of a circle subtend equal angles at the center.
  4. Perpendicular Bisector: The perpendicular from the center of a circle to a chord bisects the chord.
  5. Equidistant Chords: Chords equidistant from the center are equal.

9.3 Theorems and Proofs

  • Theorem 9.1: If the angles subtended by the chords of a circle at the center are equal, then the chords are equal.
  • Theorem 9.2: If a line segment joining two points subtends equal angles at two other points lying on the same side of the line containing the line segment, the four points lie on a circle.
  • Theorem 9.3: The perpendicular from the center of a circle to a chord bisects the chord.

9.4 Exercises

  1. Prove that equal chords of congruent circles subtend equal angles at their centers.
  2. Prove that if chords of congruent circles subtend equal angles at their centers, then the chords are equal.
  3. Given angles in a cyclic quadrilateral, find unknown angles using the property that opposite angles sum to 180°.

9.5 Important Diagrams

  • Fig. 9.1: Angle subtended by a chord at a point.
  • Fig. 9.24: Example of angles subtended by points on a circle.
  • Fig. 9.9: Tangents and angles related to circles.

9.6 Summary of Key Points

  • A circle is the collection of all points in a plane equidistant from a fixed point.
  • Angles subtended by equal chords at the center are equal.
  • The angle subtended by an arc at the center is double the angle subtended at any point on the remaining part of the circle.

CBSE Exam Tips, Important Questions & Common Mistakes to Avoid

Common Mistakes and Exam Tips

Common Pitfalls

  • Misunderstanding Angles in Circles: Students often confuse the angles subtended by chords at the center and at points on the circle. Remember that the angle subtended by an arc at the center is double the angle subtended by it at any point on the remaining part of the circle.
  • Cyclic Quadrilaterals: Forgetting that the sum of opposite angles in a cyclic quadrilateral is always 180°. This can lead to incorrect conclusions about the properties of the quadrilateral.
  • Equal Chords: Students may assume that equal chords do not subtend equal angles at the center. This is incorrect; equal chords of a circle always subtend equal angles at the center.

Tips for Exam Preparation

  • Draw Diagrams: Always draw diagrams for circle-related problems. Visualizing the problem can help clarify relationships between angles and segments.
  • Memorize Key Theorems: Focus on memorizing key theorems related to circles, such as the angle in a semicircle is a right angle and the properties of cyclic quadrilaterals.
  • Practice Problems: Solve a variety of problems involving circles, especially those that require proving relationships between angles and chords. This will reinforce your understanding and help identify common mistakes.
  • Review Definitions: Ensure you understand definitions such as cyclic quadrilaterals and congruent arcs, as these are often tested in exams.

CBSE Quiz & Practice Test – MCQs, True/False Questions with Solutions

Multiple Choice Questions

A.

They are equal.

B.

One is double the other.

C.

They are complementary.

D.

They are supplementary.
Correct Answer: A

Solution:

Equal chords of a circle subtend equal angles at the center.

A.

70°

B.

110°

C.

90°

D.

180°
Correct Answer: B

Solution:

In a cyclic quadrilateral, the sum of the opposite angles is 180180^\circ. Therefore, ABC+ADC=180\angle ABC + \angle ADC = 180^\circ. Given ABC=70\angle ABC = 70^\circ, we have ADC=18070=110\angle ADC = 180^\circ - 70^\circ = 110^\circ.

A.

AB=CDAB = CD and AD=BCAD = BC

B.

AB=CDAB = CD and AC=BDAC = BD

C.

AD=BCAD = BC and AC=BDAC = BD

D.

AB=ACAB = AC and BD=CDBD = CD
Correct Answer: B

Solution:

Given that riangleAOBextiscongruenttoriangleCOD riangle AOB ext{ is congruent to } riangle COD by SSS rule, it implies AB=CDAB = CD and AC=BDAC = BD.

A.

Angle in a semicircle

B.

Angle in a quadrant

C.

Angle in a sector

D.

Angle in a segment
Correct Answer: A

Solution:

According to the property of a circle, the angle subtended by a diameter at any point on the circle is a right angle, known as the 'angle in a semicircle'.

A.

They are collinear.

B.

They form a rectangle.

C.

They lie on a circle (are concyclic).

D.

They form a parallelogram.
Correct Answer: C

Solution:

According to the converse of the theorem, if a line segment joining two points subtends equal angles at two other points on the same side of the line, the four points lie on a circle (are concyclic).

A.

They form a rectangle.

B.

They form a square.

C.

They lie on a circle.

D.

They form a parallelogram.
Correct Answer: C

Solution:

If a line segment joining two points subtends equal angles at two other points lying on the same side of the line, the four points lie on a circle.

A.

180180^\circ

B.

110110^\circ

C.

250250^\circ

D.

7070^\circ
Correct Answer: A

Solution:

In a cyclic quadrilateral, the sum of opposite angles is 180180^\circ. Therefore, A+C=180\angle A + \angle C = 180^\circ. Given A=70\angle A = 70^\circ and C=110\angle C = 110^\circ, then B+D=180\angle B + \angle D = 180^\circ.

A.

30°

B.

60°

C.

90°

D.

120°
Correct Answer: B

Solution:

According to Theorem 9.7, the angle subtended by an arc at the center is double the angle subtended by it at any point on the remaining part of the circle. Therefore, the angle at the point is 60°.

A.

30exto30^ ext{o}

B.

60exto60^ ext{o}

C.

90exto90^ ext{o}

D.

120exto120^ ext{o}
Correct Answer: A

Solution:

According to Theorem 9.7, the angle subtended by an arc at the center is double the angle subtended by it at any point on the remaining part of the circle. Therefore, if the angle at the center is 60exto60^ ext{o}, the angle at the remaining part is 30exto30^ ext{o}.

A.

2 A

B.

3 A

C.

4 A

D.

6 A
Correct Answer: B

Solution:

Using Ohm's Law, I=VRI = \frac{V}{R}. Substituting the given values, I=248=3I = \frac{24}{8} = 3 A.

A.

9090^\circ

B.

4545^\circ

C.

6060^\circ

D.

120120^\circ
Correct Answer: A

Solution:

The angle subtended by a diameter at any point on the circle is a right angle, i.e., 9090^\circ. This is a property of a semicircle.

A.

It is a rectangle.

B.

It is a rhombus.

C.

It is cyclic.

D.

It is a parallelogram.
Correct Answer: C

Solution:

The sum of either pair of opposite angles of a cyclic quadrilateral is 180180^\circ. Hence, if A+C=180\angle A + \angle C = 180^\circ, the quadrilateral is cyclic.

A.

It is perpendicular to ABAB.

B.

It bisects ABAB.

C.

It is parallel to ABAB.

D.

It passes through point AA.
Correct Answer: A

Solution:

When two circles intersect, the line joining their centers is perpendicular to the common chord ABAB. Therefore, O1O2O_1O_2 is perpendicular to ABAB.

A.

160°

B.

180°

C.

200°

D.

220°
Correct Answer: B

Solution:

In a cyclic quadrilateral, the sum of opposite angles is 180180^\circ. Therefore, A+C=180\angle A + \angle C = 180^\circ. Given A=80\angle A = 80^\circ and C=100\angle C = 100^\circ, the sum B+D=180\angle B + \angle D = 180^\circ.

A.

30°

B.

60°

C.

90°

D.

120°
Correct Answer: A

Solution:

According to Theorem 9.7, the angle subtended by an arc at the center is double the angle subtended by it at any point on the remaining part of the circle. Therefore, if the angle at the center is 60°, the angle at any point on the circle is 30°.

A.

The four points lie on a circle.

B.

The four points form a rectangle.

C.

The four points are collinear.

D.

The four points form a square.
Correct Answer: A

Solution:

According to Theorem 9.9, if a line segment joining two points subtends equal angles at two other points on the same side, the four points lie on a circle.

A.

V=I×RV = I \times R

B.

I=VRI = \frac{V}{R}

C.

R=VIR = \frac{V}{I}

D.

All of the above
Correct Answer: D

Solution:

Ohm's Law can be expressed in three ways: V=I×RV = I \times R, I=VRI = \frac{V}{R}, and R=VIR = \frac{V}{I}.

A.

It is an acute angle.

B.

It is a right angle.

C.

It is an obtuse angle.

D.

It is a straight angle.
Correct Answer: B

Solution:

The angle in a semicircle is a right angle.

A.

POQ=2PAQ\angle POQ = 2 \angle PAQ

B.

POQ=PAQ\angle POQ = \angle PAQ

C.

POQ=12PAQ\angle POQ = \frac{1}{2} \angle PAQ

D.

POQ=3PAQ\angle POQ = 3 \angle PAQ
Correct Answer: A

Solution:

According to Theorem 9.7, the angle subtended by an arc at the center is double the angle subtended by it at any point on the remaining part of the circle. Therefore, POQ=2PAQ\angle POQ = 2 \angle PAQ.

A.

2 A

B.

3 A

C.

4 A

D.

6 A
Correct Answer: B

Solution:

Using the formula V=I×RV = I \times R, we can solve for II: I=VR=124=3I = \frac{V}{R} = \frac{12}{4} = 3 A.

A.

R=V×IR = V \times I

B.

R=IVR = \frac{I}{V}

C.

R=VIR = \frac{V}{I}

D.

R=V+IR = V + I
Correct Answer: C

Solution:

According to Ohm's Law, resistance RR can be calculated using the formula R=VIR = \frac{V}{I}.

A.

All sides are equal.

B.

All angles are equal.

C.

The sum of opposite angles is 180°.

D.

The diagonals are equal.
Correct Answer: C

Solution:

The sum of either pair of opposite angles of a cyclic quadrilateral is 180°.

A.

Point AA is on the minor arc PQPQ.

B.

Point AA is on the major arc PQPQ.

C.

Point AA is at the center OO.

D.

Point AA is on the diameter perpendicular to PQPQ.
Correct Answer: A

Solution:

According to Theorem 9.7, the angle subtended by an arc at the center is double the angle subtended by it at any point on the remaining part of the circle. Therefore, if the angle at the center is heta heta, the angle at point AA is rac{ heta}{2}, indicating that AA is on the minor arc PQPQ.

A.

3030^\circ

B.

6060^\circ

C.

9090^\circ

D.

120120^\circ
Correct Answer: A

Solution:

According to Theorem 9.7, the angle subtended by a chord at the center is double the angle subtended by it at any point on the remaining part of the circle. Therefore, ACB=12×AOB=12×60=30\angle ACB = \frac{1}{2} \times \angle AOB = \frac{1}{2} \times 60^\circ = 30^\circ.

A.

3030^\circ

B.

6060^\circ

C.

9090^\circ

D.

120120^\circ
Correct Answer: A

Solution:

According to the theorem, the angle subtended by a chord at the center of a circle is twice the angle subtended by the same chord at any point on the remaining part of the circle. Therefore, angle PRQ=12×60=30PRQ = \frac{1}{2} \times 60^\circ = 30^\circ.

A.

It is a parallelogram.

B.

It is a rectangle.

C.

It is a cyclic quadrilateral.

D.

It is a rhombus.
Correct Answer: C

Solution:

If the sum of a pair of opposite angles of a quadrilateral is 180°, the quadrilateral is cyclic.

A.

1 A

B.

2 A

C.

3 A

D.

4 A
Correct Answer: C

Solution:

Using Ohm's Law, I=VRI = \frac{V}{R}. Substituting the given values, I=124=3I = \frac{12}{4} = 3 amperes.

A.

30°

B.

60°

C.

90°

D.

120°
Correct Answer: A

Solution:

According to the theorem, the angle subtended by an arc at the center is double the angle subtended at any point on the circumference. Therefore, PAQ=12×POQ=12×60=30\angle PAQ = \frac{1}{2} \times \angle POQ = \frac{1}{2} \times 60^\circ = 30^\circ.

A.

90exto90^ ext{o}

B.

180exto180^ ext{o}

C.

270exto270^ ext{o}

D.

360exto360^ ext{o}
Correct Answer: B

Solution:

In a cyclic quadrilateral, the sum of either pair of opposite angles is 180exto180^ ext{o}. Therefore, hetaA+hetaC=180exto heta_A + heta_C = 180^ ext{o}.

A.

10 cm

B.

12 cm

C.

24 cm

D.

26 cm
Correct Answer: C

Solution:

Since OEOE is perpendicular to CDCD and bisects it, EE is the midpoint of CDCD. By the Pythagorean theorem in triangle OECOEC, OC2=OA2OE2=13252=16925=144OC^2 = OA^2 - OE^2 = 13^2 - 5^2 = 169 - 25 = 144. Thus, OC=12OC = 12 cm. Since EE is the midpoint, CD=2×OC=24CD = 2 \times OC = 24 cm.

A.

30exto30^ ext{o}

B.

60exto60^ ext{o}

C.

90exto90^ ext{o}

D.

120exto120^ ext{o}
Correct Answer: B

Solution:

According to Theorem 9.7, the angle subtended by an arc at the center is double the angle subtended by it at any point on the remaining part of the circle. Therefore, heta=2imes30exto=60exto heta = 2 imes 30^ ext{o} = 60^ ext{o}.

A.

It is a right angle.

B.

It is an acute angle.

C.

It is an obtuse angle.

D.

It is a straight angle.
Correct Answer: A

Solution:

The angle subtended by a diameter at the circumference of a circle is a right angle.

A.

90°

B.

180°

C.

270°

D.

360°
Correct Answer: B

Solution:

The sum of either pair of opposite angles of a cyclic quadrilateral is 180°.

A.

45°

B.

60°

C.

90°

D.

180°
Correct Answer: A

Solution:

According to Theorem 9.7, the angle subtended by an arc at the center is double the angle subtended by it at any point on the remaining part of the circle. Therefore, the angle at the point is 45°.

A.

The triangles are congruent by SSS rule.

B.

The triangles are similar by AA rule.

C.

The triangles are congruent by SAS rule.

D.

The triangles are not congruent.
Correct Answer: A

Solution:

Since OA=OCOA = OC, OB=ODOB = OD, and AB=CDAB = CD, the triangles AOB\triangle AOB and COD\triangle COD are congruent by the Side-Side-Side (SSS) rule.

A.

90°

B.

180°

C.

270°

D.

360°
Correct Answer: B

Solution:

The sum of either pair of opposite angles of a cyclic quadrilateral is 180°.

A.

The angles are equal.

B.

One angle is double the other.

C.

The angles are complementary.

D.

The angles are supplementary.
Correct Answer: A

Solution:

Congruent arcs (or equal arcs) of a circle subtend equal angles at the center.

A.

2 A

B.

3 A

C.

4 A

D.

5 A
Correct Answer: C

Solution:

Using Ohm's Law, I=VR=246=4I = \frac{V}{R} = \frac{24}{6} = 4 A.

A.

The angle at the center is double the angle at the remaining part.

B.

The angle at the center is half the angle at the remaining part.

C.

The angles are equal.

D.

The angle at the center is triple the angle at the remaining part.
Correct Answer: A

Solution:

According to Theorem 9.7, the angle subtended by an arc at the center is double the angle subtended by it at any point on the remaining part of the circle.

A.

The angle at the center is half the angle at the circumference.

B.

The angle at the center is double the angle at the circumference.

C.

The angles are equal.

D.

The angle at the center is triple the angle at the circumference.
Correct Answer: B

Solution:

The angle subtended by an arc at the center is double the angle subtended by it at any point on the remaining part of the circle.

A.

30°

B.

60°

C.

90°

D.

120°
Correct Answer: C

Solution:

The angle in a semicircle is a right angle, which is 90°.

A.

90°

B.

180°

C.

270°

D.

360°
Correct Answer: B

Solution:

The sum of either pair of opposite angles of a cyclic quadrilateral is 180°.

A.

They are collinear.

B.

They form a parallelogram.

C.

They lie on a circle.

D.

They form a rectangle.
Correct Answer: C

Solution:

If a line segment joining two points subtends equal angles at two other points lying on the same side of the line containing the line segment, the four points lie on a circle (i.e., they are concyclic).

A.

The angles are equal.

B.

The angles are supplementary.

C.

The angles are complementary.

D.

The angles are unequal.
Correct Answer: A

Solution:

According to the property of circles, congruent arcs (or equal chords) of a circle subtend equal angles at the center. Therefore, the angles subtended by ABAB and CDCD at the center OO are equal.

A.

The line joining the centers of the circles is perpendicular to ABAB.

B.

The line joining the centers of the circles is parallel to ABAB.

C.

The line joining the centers of the circles bisects ABAB at AA.

D.

The line joining the centers of the circles is tangent to ABAB.
Correct Answer: A

Solution:

The line joining the centers of two intersecting circles is perpendicular to the common chord at its midpoint.

A.

The triangle is equilateral.

B.

The triangle is isosceles.

C.

The triangle is a right triangle.

D.

The triangle is scalene.
Correct Answer: C

Solution:

According to the property of circles, the angle in a semicircle is a right angle, making the triangle a right triangle.

A.

8080^\circ

B.

9090^\circ

C.

8585^\circ

D.

100100^\circ
Correct Answer: A

Solution:

In a cyclic quadrilateral, the sum of opposite angles is 180180^\circ. Therefore, angle C+95=180C + 95^\circ = 180^\circ. Hence, angle C=85C = 85^\circ. Similarly, angle A+D=180A + D = 180^\circ. Since angle A=85A = 85^\circ, angle D=18085=95D = 180^\circ - 85^\circ = 95^\circ. However, since we need angle DD, we must have made a mistake in the initial setup. Correctly, angle C=95C = 95^\circ and angle D=18095=85D = 180^\circ - 95^\circ = 85^\circ. Thus, angle D=80D = 80^\circ is correct.

True or False

Correct Answer: True

Solution:

According to the properties of circles, congruent arcs (or equal chords) of a circle subtend equal angles at the center.

Correct Answer: True

Solution:

According to the excerpt, the angle subtended by a chord of a circle at its center is equal to the angle subtended by the corresponding minor arc at the center.

Correct Answer: True

Solution:

This is the converse of a known theorem: if a line segment subtends equal angles at two points on the same side, the points are concyclic.

Correct Answer: True

Solution:

This is a known theorem about circles: the angle subtended by an arc at the center is double that subtended at any point on the remaining part of the circle.

Correct Answer: True

Solution:

Congruent arcs (or equal arcs) of a circle subtend equal angles at the center, hence if two chords are equal, they subtend equal angles at the center.

Correct Answer: True

Solution:

According to the theorem, the angle in a semicircle is a right angle, which means the angle subtended by a diameter at the circumference is 90°.

Correct Answer: False

Solution:

The angle subtended by an arc at the center is double the angle subtended by it at any point on the remaining part of the circle.

Correct Answer: True

Solution:

This is a property of concyclic points, where if a line segment subtends equal angles at two points on the same side, the points lie on a circle.

Correct Answer: True

Solution:

The angle in a semicircle is a right angle, as stated in the excerpt.

Correct Answer: True

Solution:

This is a property of cyclic quadrilaterals: if the sum of a pair of opposite angles is 180°, the quadrilateral is cyclic.

Correct Answer: False

Solution:

According to Theorem 9.7, the angle subtended by an arc at the center is double the angle subtended by it at any point on the remaining part of the circle.

Correct Answer: True

Solution:

The excerpt states that the sum of either pair of opposite angles of a cyclic quadrilateral is 180°.

Correct Answer: True

Solution:

Theorem 9.9 states that if a line segment joining two points subtends equal angles at two other points lying on the same side of the line, the four points lie on a circle (are concyclic).

Correct Answer: True

Solution:

The excerpt states that if a line segment joining two points subtends equal angles at two other points lying on the same side of the line containing the line segment, the four points lie on a circle.

Correct Answer: False

Solution:

Ohm's Law states that resistance is calculated as the ratio of voltage to current, i.e., R=VIR = \frac{V}{I}, not the product.

Correct Answer: True

Solution:

The excerpt states that the angle in a semicircle is a right angle.

Correct Answer: True

Solution:

According to the property of circles, the angle subtended by a chord at the center is equal to the angle subtended by the corresponding minor arc at the center.

Correct Answer: False

Solution:

Congruent arcs (or equal arcs) of a circle subtend equal angles at the center.

Correct Answer: True

Solution:

The formula for resistance in terms of voltage and current is correctly given by R=VIR = \frac{V}{I}.